◆ Define the variables:
Let the calorie content of Candy A = a
and the calorie content of Candy B = b
◆ Form the equations:
One bar of candy A and two bars of candy B have 774 calories. Thus:
a + 2b = 774
Two bars of candy A and one bar of candy B contains 786 calories
2a + b = 786
◆ Solve the equations:
From first equation,
a + 2b = 774
=> a = 774 - 2b
Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie
◆ Find caloric content:
Caloric content of candy B = 254 calorie
Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
Answer: 333 degrees
Step-by-step explanation:
Step-by-step explanation:
this sequence is geometric not arithmetic
HOw we know that ??
when we get a common difference that must Be equal
d=6-2=4 not equal to d=18-6=12
So it is not arithmetic
but when we get the common ratio that also must be equal
r=6/2=18/6=54/18=3 equal
So it is geometric
By using this equation:
a(n)=a(1)*r^(n-1)
and we have a(1)=2 , r=3
<u>Explicit rule:</u> a(n)=2*(3)^(n-1)
<u>Recursive rule:</u> a(n)= r * a(n-1)
a(n-1) ⇒ priviuse term
SO: a(n)= 3 * a(n-1)
For example:
a(3)= 3 * 6 =18
<em>I really hope this helps <3</em>
Could you attach photo of a problem. It appears 2+..... =4 is missing