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balu736 [363]
3 years ago
8

Which of the following are solutions to the equation below?

Mathematics
1 answer:
Luden [163]3 years ago
4 0

Answer:

c) -4/5

d) 4/5

Step-by-step explanation:

The given equation is 25x^2 -16 = 0

Adding 16 on both sides, we get

25x^2 = 16

Dividing both sides by 25, we get

x^2 = 16/25

Taking square root on both sides, we get

x = √(16/25)

x = ±4/5

Therefore, x = 4/5 and x = -4/5

Answers: C) and D)

Hope this will helpful to understand the concept.

Thank you.

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URGENT! Which equation represents a line that passes through the two points in the table?
iVinArrow [24]

Answer:

A. y-1=5/4(x-1)

Step-by-step explanation:

This is written in point slope form, which is Y-Y1=m(X-X1)

X1 and Y1 can be seen as the coordinates in the table (1,1)

So plug in the negative values following the point-slope formula:

Y-1=5/4(X-1)

8 0
3 years ago
Find the value of x number on top is 6 and other is 9
faltersainse [42]

Answer:

x = - 12, 3

Step-by-step explanation:

By tangent secant theorem:

x(x + 9) =  {6}^{2}  \\  \\  {x}^{2}  + 9x = 36 \\  \\  {x}^{2}  + 9x - 36 = 0 \\  \\  {x}^{2}  + 12x - 3x - 36 = 0 \\  \\ x(x + 12) - 3(x + 12) = 0 \\  \\ (x + 12)(x - 3) = 0 \\  \\ x + 12 = 0, \:  \: x - 3 = 0 \\  \\ x =  - 12, \:  \: x = 3 \\  \\

5 0
3 years ago
Suppose the heights of the members of a population follow a normal distribution. If the mean height of the population is 68 inch
jekas [21]

Answer:

68% of the population will have a height between 64 and 72 inches

Step-by-step explanation:

According to the Empirical Rule, 68% of the population will have a height within the range of 1 standard deviation of the mean. This means that the range of possible heights for 68% of the population is between 68-4(1)=64 inches and 68+4(1)=72 inches

6 0
3 years ago
The length of a rectangle is the sum of the width and 4. The area of the rectangle is 32
Sauron [17]

Answer:

The width of rectangle w = 4 units

Step-by-step explanation:

We are given:

Width of rectangle = w

Length of rectangle = w+ 4

Area of rectangle = 32 units

We need to find width of the rectangle

The formula used is: Area\:of\:rectangle=Length\times Width

Putting values and finding width of rectangle

Area\:of\:rectangle=Length\times Width\\32=(w+4)\times w\\32=w^2+4w\\w^2+4w-32=0

We need to solve this quadratic equation to find width (w)

We will use factorisation and break the middle term.

w^2+4w-32=0\\w^2+8w-4w-32=0\\w(w+8)-4(w+8)=0\\(w-4)(w+8)=0\\w-4=0\:or\:w+8=0\\w=4\:or\:w=-8

Since width of rectangle can't be negative, so rejecting w=-8

Therefore, the width of rectangle w = 4 units

4 0
3 years ago
If g(x) = 3 - 2x find, g(-1)​
pogonyaev

Steps to solve:

g(x) = 3 - 2x when g(-1)

~Substitute

g(-1) = 3 - 2(-1)

~Simplify

g(-1) = 3 - (-2)

~Simplify

g(-1) = 3 + 2

~Add

g(-1) = 5

Best of Luck!

3 0
4 years ago
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