3 years ago

What is the vertex of the function x^2-6x+8=0 ?

Mathematics

1 answer:

3241004551 [841]3 years ago

5 0

-6 / 2 = -3 so
x^2 - 6x + 8 is
(x - 3)^2 -9 + 8

= (x - 3)^2 - 1

the vertex is at (3,-1)

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