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Jet001 [13]
2 years ago
12

A 4 kg bowling ball moving at 1.4 m/s east impacts a 400 g pin that is stationary. After the impact, the ball is moving at 0.5 m

/s east. Assuming the collision was elastic, what speed does the pin move at after being struck?
Physics
1 answer:
nignag [31]2 years ago
3 0

The speed of the pin after the elastic collision is 9 m/s east.

<h3>Final speed of the pin</h3>

The final speed of the pin is calculated by applying the principle of conservation of linear momentum as follows;

m1u1 + mu2 = m1v1 + m2v2

where;

  • m is the mass of the objects
  • u is the initial speed of the objects
  • v is the final speed of the objects

4(1.4) + 0.4(0) = 4(0.5) + 0.4v2

5.6 = 2 + 0.4v2

5.6 - 2 = 0.4v2

3.6 = 0.4v2

v2 = 3.6/0.4

v2 = 9 m/s

Thus, The speed of the pin after the elastic collision is 9 m/s east.

Learn more about linear momentum here: brainly.com/question/7538238

#SPJ1

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3 years ago
1.00 x 10^8 kg of clear liquid (specific heat
pshichka [43]
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3 0
3 years ago
A meter stick is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other end when it
Tems11 [23]

Answer:

5.4 ms⁻¹

Explanation:

Here we have to use conservation of energy. Initially when the stick is held vertical, its center of mass is at some height above the ground, hence the stick has some gravitational potential energy. As the stick is allowed to fall, its rotates about one. gravitational potential energy of the stick gets converted into rotational kinetic energy.

L = length of the meter stick = 1 m

m = mass of the meter stick

w = angular speed of the meter stick as it hits the floor

v = speed of the other end of the stick

we know that, linear speed and angular speed are related as

v = r w\\w = \frac{v}{r}

h = height of center of mass of meter stick above the floor = \frac{L}{2} = \frac{1}{2} = 0.5 m

I = Moment of inertia of the stick about one end

For a stick, momentof inertia about one end has the formula as

I = \frac{mL^{2} }{3}

Using conservation of energy

Rotational kinetic energy of the stick = gravitational potential energy

(0.5) I w^{2} = mgh\\(0.5)(\frac{mL^{2} }{3}) (\frac{v}{L} )^{2} = mgh\\(0.5)(\frac{v^{2} }{3}) = gh\\(0.5)(\frac{v^{2} }{3}) = (9.8)(0.5)\\v = 5.4 ms^{-1}

7 0
4 years ago
Which of the following statements is true for ideal gases, but is not always true for real gases?
xxMikexx [17]

Answer:

C. Replacing one gas by another under the same conditions, has no effect on pressure.

Explanation:

Ideal gas:

 A gas is treated as an ideal gas if temperature is high and pressure is low.

Kinetic energy for ideal gas given as

K.E.=\dfrac{3}{2}KT

So when temperature of gas is increases then  Average molecular kinetic energy will also increases.

The size of molecule is negligible as compare to the dimension of container. It mean that volume occupied by molecule is less as compare to the volume of container.

The between molecules is perfectly elastic.

Ideal gas equation

P V = m R T

So the option C is not always true.

4 0
3 years ago
Carbon cycle diagram
sammy [17]

Carbon cycle shows is the continous movement of carbon in elemental and combined states on earth.

Steps :-

☆ Carbon moves from the atmosphere to plants. ...

☆ Carbon moves from plants to animals. ...

☆ Carbon moves from plants and animals to soils. ...

☆ Carbon moves from living things to the atmosphere. ...

☆ Carbon moves from fossil fuels to the atmosphere when fuels are burned. ...

☆ Carbon moves from the atmosphere to the oceans.

~ Benhemin360

6 0
3 years ago
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