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Mariulka [41]
4 years ago
12

Eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Chemistry
1 answer:
Ann [662]4 years ago
4 0
The answer is c because ice is cold
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Where do expect to find the most reactive metals on the periodic table;?
faltersainse [42]
The most reactive metals on the periodic table would have to be the alkali metals.
I hope this helps!
Have a nice day (:
5 0
3 years ago
Read 2 more answers
Draw the product formed when oleic acid is hydrogenated.
lesya [120]

Oleic acid belongs to class of alkene and in alkenes, addition of H-H across C=C that is carbon carbon double bond results in the formation of alkane as a product in the presence of specific catalyst such as nickel, palladium and platinum.  The reaction is said to be hydrogenation reaction.

Oleic acid (C_{17}H_{33}COOH) consist of 17 carbon atoms attached to 33 hydrogen atoms with one double bond between two carbon atoms and one carboxylic group i.e.(-COOH). When oleic acid is hydrogenated or reacts with hydrogen in the presence of catalyst, then the carbon carbon double breaks by the addition H-H and alkane product i.e. stearic acid  (C_{17}H_{35}COOH) is formed.

The chemical reaction is shown in the image.

7 0
3 years ago
Which factor is a major contributor to outdoor air pollution?.
Anni [7]
Outdoor pollution primarily results from the combustion of fossil fuels by industrial plants and vehicles. This releases carbon monoxide, sulfur dioxide, particulate matter, nitrogen oxides, hydrocarbons and other pollutants.
6 0
2 years ago
The decomposition reaction of carbon disulfide to carbon monosulfide and sulfur is first order with k = 2.80 ✕ ✕ 10−7 sec-1 at 1
madam [21]

Answer: a) 1.97 grams of carbon disulfide will remain after 37.0 days.

              b) 2.85 grams of carbon monosulfide will be formed after 37.0 days.

Explanation: The decomposition of carbon disulfide is given as:

                          CS_2(g)\rightarrow CS(g)+S(g)

at t=0                    4.83g             0          0

at t=37 days        4.83 - x            x           x

here,

x = amount of CS_2 utilised in the reaction

This reaction follows first order kinetics so the rate law equation is:

k=\frac{2.303}{t}log\frac{A_o}{A}

where, k = rate constant

t = time

A_o = Initial mass of reactant

A = Final mass of reactant

a) For this, the value of

k=2.80\times10^{-7}sec^{-1}

t = 370 days = 3196800 sec

A_o = 4.83

A = 4.83-x

Putting values in the above equation, we get

2.8\times 10^{-7}sec^{-1}=\frac{2.303}{3196800sec}log\left(\frac{4.83}{4.83-x}\right)

x = 2.85g

Amount of CS_2 remained after 37 days = 4.83 - x

                                                                     = 1.97g

b) Amount of carbon monosulfide formed will be equal to "x" only which we have calculated in the previous part.

Amount of carbon monosulfide formed = 2.85g

6 0
3 years ago
The chemical compound, "AB" has a molar mass of 74.548 g/mol.
sladkih [1.3K]

Answer:

47.55%

Explanation:

4 0
3 years ago
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