Answer:
We need 226 grams of FeS
Explanation:
Step 1: Data given
Mass of FeCl2 = 326 grams
Molar mass FeCl2 = 126.75 g/mol
Step 2: The balanced equation
FeS + 2 HCl → H2S + FeCl2
Step 3: Calculate moles FeCl2
Moles FeCl2 = 326 grams / 126.75 grams
Moles FeCl2 = 2.57 moles
Step 4: Calculate moles FeS needed
For 1 mol H2S and 1 mol FeCl2 produced, we need 1 mol FeS and 2 moles HCl
For 2.57 moles FeCl2 we need 2.57 moles FeS
Step 5: Calculate mass FeS
Mass FeS = 2.57 moles * 87.92 g/mol
Mass FeS = 226 grams FeS
We need 226 grams of FeS
Answer:
- <em><u>Measurement of the amount of variation of the species in a given area. </u></em>
Explanation:
<em>Bio</em> preffix means life. Thus, literally, biodiversity means how diverse is the life. This is, how many different organisms an ecosystem or biome has.
Thus, biodiverstiy, although more complex than just that, is a measure of the number of species that live in a region.
The biome with most species than any other, this is the biome with the greatest biodiversity, is the tropical rainforest biome, which are located near the equator. As you can imagine, a large number of different plants, animals, and microorganisms live in these forests, making them the regions with greatest biodiversity on the planet.
Elements are separate particles that contain the properties of only one type of element (pure substance) and an atom represents that element as the smallest non divisible particle that retains the properties of that element. Compounds can be formed by conjoining different atoms together in different ratios and shapes, so a combination of elements.
Answer:Videos
For example, when oxygen and hydrogen react to produce water, one mole of oxygen ... These conversion factors state the ratio of reactants that react but do not tell ... In a typical chemical equation, an arrow separates the reactants on the left ... For example, to determine the number of mol
<span>CH4 + 4 Cl2 → CCl4 + 4 HCl
(4.00 mol CH4) x (1/1) x (0.70) = 2.80 mol CCl4
(4.00 mol CH4) x (4/1) x (0.70) = 11.2 mol HCl
CCl4 + 2 HF → CCl2F2 + 2 HCl
(2.80 mol CCl4) x (2/1) x (0.70) = 3.92 mol HCl
11.2 mol + 3.92 mol = 15.1 mol HCl from both steps</span>
