Answer: The total pressure of air in lungs of an individual is 760.28 mm Hg
Explanation:
According to Dalton's law, the total pressure is the sum of individual pressures.

Given :
=total pressure of gases = ?
= partial pressure of oxygen = 100 mm Hg
= partial pressure of nitrogen = 573 mm Hg
= partial pressure of Carbon dioxide = 0.053 atm = 40.28 mm Hg(1 atm = 760 mmHg)
= partial pressure of water vapor = 47 torr = 47 mm Hg (1torr=1 mm Hg)
putting in the values we get:
Thus the total pressure of air in lungs of an individual is 760.28 mm Hg
moles CO₂ = 5.57.10⁻⁴
<h3>Further explanation
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A mole is a number of particles(atoms, molecules, ions) in a substance
Can be formulated :

0.7% percent change with 3.5g of plant matter
mass :

moles :

The answer is N2 + 3H2 yields 2NH3. The oxidation-reduction reaction means that there is electrons transfer during the reaction which means that the valence changed.