First, draw the 2-hexene. Th is is a molecule of six carbons with a double bond in the second carbon:
CH3 - CH = CH2 - CH2 - CH2 - CH3
Secong, put one Br on the second carbon and one Br on the third carbon:
CH3 - CBr = CBr - CH2 - CH2 - CH3
Third, cis means that the two Br are placed in opposed positions, this is drawn with one Br up and the other down. So, you need to represent the position of the Br in the space:
H Br H H H
| | | | |
H - C - C = C - C - C - C - H
| | | | |
H Br H H H
The important fact to realize is that the two Br are in opposed sides of the molecule.
ANSWER: receptor-meditated endocytosis
I’m not sure if this is what you’re looking for but this is correct. Next time please add the full question and possible answers. HOPE this helps someone please leave thanks if so.
Explanation:
The question pretty much requires us to find the amount of moles of each compounds based on the number of moles of O given.
H2SO4
1 mol of H2SO4 contains 4 mol of O
x mol of H2SO4 would contain 3.10 mol of O
x = 3.10 * 1 / 4 = 0.775 mol of H2SO4
C2H4O2
1 mol of C2H4O2 contains 2 mol of O
x mol of C2H4O2 would contain 3.10 mol of O
x = 3.10 * 1 / 2 = 1.55 mol of C2H4O2
NaOH
1 mol of NaOH contains 1 mol of O
x mol of NaOH would contain 3.10 mol of O
x = 3.10 * 1 / 1 = 3.10 mol of NaOH
Reaction:
Magnesium is a stronger reducing agent than copper and is thus able to reduce copper(II) oxide.
Products of the reaction: Magnesium oxide and metallic copper.
