Answer:
<em>0.15M</em>
Explanation:
Molar Concentration =
Assuming 20g of the unadulterated aluminium chloride was weighed into the volumetric flask, and given molar mass of AlCl3 = 133.34g/mol
∴ Molarity =
= 0.14999 ≈ <em><u>0.15M (to 2 significant figures)</u></em>
I hope this solution is clear. The same can be calculated from concentration by volume.
Answer:
The molecular weight (molar mass) of any gas is the mass of one particle of that gas multiplied by Avogadro's number (6.02 x 1023).
Explanation:
How do you find the molar mass of a gas?
First the ideal gas law will be used to solve for the moles of unknown gas (n). Then the mass of the gas divided by the moles will give the molar mass.
Answer:
4.48 grams of potassium hydroxide that the chemist must be weighing out.
Explanation:
The pH of the KOH solution = 13
pH + pOH = 14
pOH = 14 - pH = 14 - 13 = 1
1 mole of hydroxide ions are obtained from 1 mole of KOH. Then 0.1 mole of hydroxide ions will be obtained from :
of KOH
Volume of KOH solution = 800 mL = 0.800 L ( 1 mL = 0.001 L)
Moles of KOH = 0.1 M × 0.800 L = 0.08 mol
Mass of 0.08 moles of KOH :
0.08 mol × 56 g/mol = 4.48 g
4.48 grams of potassium hydroxide that the chemist must be weighing out.
Answer:
1.VOLUME– The amount of space an object takes up. Basic Unit (SI Unit) for Solids – Cubic Meter, m3. LENGTH/DISTANCE – The measurement between two points.
2.one particle per cubic meter.
3.it means it is heavier
4.In a liquid the particles are still close together but a little further apart than in a solid.
5.In gases the particles are much further apart than in solids or liquids.
Explanation:
thats all i can type lol
Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...
Using an ionic chloride and Phosphoric acid
H3PO4 + NaCl ==> HCl + NaH2PO4
H3PO4 + NaI ==> HI + NaH2PO4
H2SO4 + NaCl ==> HCl + NaHSO4
This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.
The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.
2I-² === I2 + 2e-