After the water is boiled off, the mass is 9.7 grams, so find the weight of the water.
12.98 - 9.7 = 3.28g H2O
Find how many moles of CuSO4 and H2O you have.
If there are about 18g per mole of H2O
3.28/18 = .1822 moles of H2O
If there are about 160g per mole of CuSO4
9.7/160 = .0606 moles of CuSO4
.1822/.0606 = 3
Ratio of H2O to CuSO4 = 1:3
Formula
<span>CuSO4.3H2O
</span>
Full Name
<span>Copper (II) Sulphate Trihydrate</span>
Answer:
Al + MnO4- + 2H2O → Al(OH)4- + MnO2
Explanation:
First of all, we out down the skeleton equation;
Al + MnO4- → MnO2 + Al(OH)4-
Secondly, we write the oxidation and reduction equation in basic medium;
Oxidation half equation:Al + 4H2O + 4OH- → Al(OH)4- + 4H2O + 3e-
Reduction half equation:MnO4- + 4H2O + 3e- → MnO2 + 2H2O + 4OH-
Thirdly, we add the two half reactions together to obtain:
Al + MnO4- + 8H2O + 4OH- + 3e- → Al(OH)4- + MnO2 + 6H2O + 3e- + 4OH-
Lastly, cancel out species that occur on both sides of the reaction equation;
Al + MnO4- + 8H2O→ Al(OH)4- + MnO2 + 6H2O
The simplified equation now becomes;
Al + MnO4- + 2H2O → Al(OH)4- + MnO2
Answer:
In both cases, that is the mass of 6.02 × 1023 representative particles. The representative particle of CO2 is the molecule, while for Na2S, it is the formula unit.
Explanation:
Octet law states that every atom tries to attain a octet valence shell (8 electrons in their valence shell) to attain a more stable state. For attaining this they form bonds(covalent,ionic etc) with other atoms. Please ask if you any more doubt on this, I'll try to help
