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Alex787 [66]
3 years ago
13

Hydrogen iodide is not produced by the same method is for hydrogen chloride why with reaction​

Chemistry
1 answer:
Masja [62]3 years ago
5 0

Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...

Using an ionic chloride and Phosphoric acid

H3PO4 + NaCl ==> HCl + NaH2PO4

H3PO4 + NaI ==> HI + NaH2PO4

H2SO4 + NaCl ==> HCl + NaHSO4

This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.

The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.

2I-² === I2 + 2e-

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Calculate the number of moles of gas in the following at STP: 45.6 L of H2 gas
zimovet [89]

Answer:

2.04 mol

Explanation:

At STP, 1 mole = 22.4 L

45.6 L of H2 *    (1 mole of H2 / 22.4 L ) =  2.04 mol

8 0
3 years ago
How many ml of co2 would be produced at 745 torr and 28°C
Marizza181 [45]

Answer:

Se aplica la leyes d ellos gases ideales para esto se convierten las unidades de Presión en atmósferas y Temperatura a Kelvin y si no se tiene el volumen el volumen equivale a 22.4Litros

Explanation:

3 0
3 years ago
True or false: the smaller the difference between the average experimental value and the correct (true) value the greater the ac
mel-nik [20]

Answer:

True

Explanation:

The accuracy level is usually determined by the difference between the experimental and correct value. It is important to note that the smaller the difference between the average experimental value and the correct (true) value, the more accurate it is.

When the difference is large then it means the accuracy level is low and not up to the required standard.

5 0
3 years ago
If anyone could please help me i'd greatly appreciate it! I have tried over and over again and can not figure this out.
Papessa [141]

Answer:

%Ionization = 1.63%

Explanation:

Hydrazine in aqueous media theoretically forms a difunctional hydroxyl system. However, for this problem assume only monofunctional ionization occurs. A second hydroxyl ionization would not likely occur as the formal cationic charge formed in the 1st ionization would inhibit a second ionization.

H₂NNH₂ + 2H₂O => HONHNHOH => HONHNH⁺ + OH⁻; Kb = 1.3 x 10⁻⁶

So, assuming all OH⁻ and HONHNH⁺ are delivered in the 1st ionization then a good estimate of the %ionization can be calculated.

               HONHNHOH => HONHNH⁺  +  OH⁻

C(i) =>              0.490M                  0M           0M

ΔC =>                  -x                         +x             +x

C(eq) =>         0.490 - x                    x               x

                      ≅0.490M* => *x is dropped as Conc H₂NNH₂/Kb > 100

Kb = [HONHNH⁺][OH⁻]/[HONHNHOH]

1.3 x 10⁻⁶ = x²/0.490

=> x = [OH⁻] = [HONHNH⁺] = √[(1.3 x 10⁻⁶)(0.490)] = 8 x 10⁻⁴

=> %Ionization = (x/0.490)100% = (8 x 10⁻⁴/0.490)100% = 1.63%

7 0
3 years ago
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It's not a food web it's a food chain. I just did the exam a few minutes ago. Please mark it Brainliest.

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