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Elza [17]
3 years ago
11

Which factors will increase the speed of a sound wave in the air?

Physics
1 answer:
Dafna11 [192]3 years ago
7 0
A higher temperature, stiffer materials, and less dense materials increase the speed of sound.
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When bill butcher of port city brews discusses shelf space and the way that a merger could increase the leverage potential of la
lozanna [386]

He is discussing Bargaining Power of Buyers competitive force.

What do you understand by  leverage?

The employment of various financial instruments or borrowed cash, or leverage, is an investing strategy that aims to improve an investment's potential return. The level of debt a company utilizes to finance its assets is another definition of leverage.

It offers a range of funding options so that the company can reach its desired earnings. Leverage is a crucial investing strategy because it enables businesses to establish a ceiling for the growth of their operations.

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6 0
1 year ago
Water flows through a cast steel pipe (k = 50 W m.K, ε = 0.8) with an outer diameter of 104mm and 2 mm wall thickness. Calculate
masha68 [24]

Answer:

The heat loss per unit length is   \frac{Q}{L}   = 2981 W/m

Explanation:

From the question we are told that

     The outer diameter of the pipe is d = 104mm = \frac{104}{1000} = 0.104 m

     The thickness is  D = 2mm = \frac{2}{1000} = 0.002m  

      The temperature  of water is  T = 90^oC = 90 + 273 = 363K  

      The outside air temperature is T_a = -10^oC = -10 +273 = 263K

        The water side heat transfer coefficient is z_1 = 300 W/ m^2 \cdot K

       The  heat transfer coefficient is  z_2 = 20 W/m^2 \cdot K

The heat lost per unit length is mathematically represented as

           \frac{Q}{L}   = \frac{2 \pi (T - Ta)}{ \frac{ln [\frac{d}{D} ]}{z_1}  +  \frac{ln [\frac{d}{D} ]}{z_2}}

Substituting values

         \frac{Q}{L}   = \frac{2 * 3.142 (363 - 263)}{ \frac{ln [\frac{0.104}{0.002} ]}{300}  +  \frac{ln [\frac{0.104}{0.002} ]}{20}}

           \frac{Q}{L}   = \frac{628}{0.2107}

           \frac{Q}{L}   = 2981 W/m

6 0
3 years ago
Which of the following equations can be used to directly calculate an object's impulse?
Iteru [2.4K]
I believe the answer is B
7 0
3 years ago
Jessica decides not to skip school because she does not want to lose her senior privileges if caught. Jessica is at what level o
Elena L [17]

This one is also using pre-conventional moral reasoning.

3 0
3 years ago
A small ball with mass 2.50 kg is mounted on one end of a rod 0.750 m long and of negligible mass. The system rotates in a horiz
alina1380 [7]

Answer:

1.40625 kg-m^2

Explanation:

Supposing we have to calculate rotational moment of inertia

Given:

Mass of the ball m= 2.50 kg

Length of the rod, L= 0.78 m

The system rotates in a horizontal circle about the other end of the rod

The constant angular velocity of the system, ω= 5010 rev/min

The rotational inertia of system is equal to rotational inertia of the the ball about other end of the rod because the rod is mass-less

I_{sys}= mL^2= 2.50\times 0.75^2

=1.40625 kg-m^2

m= mass of the ball and L= length of the ball

3 0
3 years ago
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