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lara [203]
2 years ago
7

Megan was doing time trials on her bike around a 400m horizontal track. She took 32 seconds to travel 400m. What was her average

speed
Physics
2 answers:
Bumek [7]2 years ago
8 0

Answer:

The answer is Average speed is equal to 12.5 m/sec

Explanation:

1- The average speed is the relationship between the distance traveled that a body made and the total time it took to perform it.

2- The formula that allows to calculate the average velocity is V = ΔX/ΔT where (V) is the average speed, (ΔX) is the distance traveled and (ΔT) is the time interval.

3- Knowing this we can replace the values given in the problem:

V = \frac{400m}{32sec} \\V = 12.5  m/sec

Mars2501 [29]2 years ago
5 0
To find average speed, we divide the distance of travel (in this case, 400 metres) by the time she took, 32 seconds.  Therefore: 12.5 seconds is her average speed.
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Which of the following is not an essential feature of scientific explanations?
sineoko [7]

Answer:

D I think I might be wrong its been a while scense I did something like that

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3 years ago
A uniform marble rolls down a symmetrical bowl, start- ing from rest at the top of the left side. The top of each side is a dist
Paha777 [63]

Answer:

Part a)

h' = \frac{10}{14} h

Part b)

if both sides are rough then it will reach the same height on the other side because the energy is being conserved.

Part c)

Since marble will go to same height when it is rough while when it is smooth then it will go to the height

h' = \frac{10}{14} h

so on smooth it will go to lower height

Explanation:

As we know by energy conservation the total energy at the bottom of the bowl is given as

\frac{1}{2} mv^2 + \frac{1}{2}I\omega^2 = mgh

here we know that on the left side the ball is rolling due to which it is having rotational and transnational both kinetic energy

now on the right side of the bowl there is no friction

so its rotational kinetic energy will not change and remains the same

so it will have

\frac{1}{2}mv^2 = mgh'

now we know that

I = \frac{2}{5}mr^2

\omega = \frac{v}{r}

so we have

\frac{1}{2}mv^2 + \frac{1}{2}(\frac{2}{5}mr^2)(\frac{v}{r})^2 = mgh

\frac{1}{2}mv^2 + \frac{1}{5}mv^2 = mgh

\frac{7}{10}mv^2 = mgh

\frac{1}{2}mv^2 = \frac{10}{14}mgh

so the height on the smooth side is given as

h' = \frac{10}{14} h

Part b)

if both sides are rough then it will reach the same height on the other side because the energy is being conserved.

Part c)

Since marble will go to same height when it is rough while when it is smooth then it will go to the height

h' = \frac{10}{14} h

so on smooth it will go to lower height

6 0
3 years ago
Read 2 more answers
A 3) How far will 20 N of force stretch a spring with a spring constant of 140 N/m?​
anyanavicka [17]

Answer:

I think the answer is

Explanation:

140N/m/20N =

7m is the answer

8 0
2 years ago
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How many atoms are in 3.5 moles of sulfur
irina [24]
There are 2.1077x10^24 atoms of sulfur in 3.50 mols of sulfur.
5 0
2 years ago
An object moving at 15 m/s slows uniformly at a rate of 2.0 m/s each second for 5.0 s. What is its final speed?​
NeX [460]
Hey there!

We are given ,

Acceleration, a = -2m/s^2

Initial velocity , u = 15m/s

Time , t = 5 seconds

We know that ,
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Now , final speed ,

V = 15+(-2)(5)

V = 15-10

V = 5 m/s -> final speed

Hope this helps you dear :)
Have a good day <3

8 0
2 years ago
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