The two displacement functions are
x₁ = 4t
x₂ = -161 + 48t - 4t²
where
x₁, x₂ are in meters
t is time, s
The distance between the two objects is
x = x₁ - x₂
= 4t + 161 - 48t + 4t²
x = 4t² - 44t + 161
Write this equation in the standard form for a parabola.
x = 4[t² - 11t] + 161
= 4[ (t - 5.5)² - 5.5² ] + 161
x = 4(t-5)² + 40
Ths is a parabola that faces up and has its vertex (lowest point) at (5, 40).
Therefore the closest approach of the two objects is 40 m.
The graph of x versus t confirms the result.
Answer: The distance of the closest approach is 40 m.
Answer:
Sometimes
Explanation:
Sometimes meaning in occasions. If it is a "vampire star" not likely because they also cause they also make novas happen by sucking the gas from another star.
Answer:
R=9.
C=(2,-2,0).
Explanation:
Lets try to find how
can be written in the form of
, since then its radius R and center of coordinates C=(a,b,c) would be easily recognizable.
Since we have the terms -4x and +4y, they seem to have come from the terms
and
, and we would need to take care of the extra +4 by substracting then. More explicitly:
, as we had originally with the x terms
, as we had originally with the y terms
Which means:

Or, putting all together:


So our radius is 9 and the center is (2,-2,0).
C) because you could get hurt if certain items fall in it and you are in water