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Margaret [11]
3 years ago
10

A steel wire, 3.2 m long, has a diameter of 1.2 mm. The wire stretches 1.6 mm when it bears a load. Young's modulus for steel is

2.0 × 1011 Pa. The mass of the load is closest to
Physics
1 answer:
Troyanec [42]3 years ago
8 0

Answer:

The mass, m, of the load = 11.3 Kg

Explanation:

Young's Modulus = Stress / Strain

<em>Stress = Force / Area </em>

Force = mass,m * acceleration due to gravity,g  

assuming g = 10ms⁻²

therefore, Force = 10m

m is mass of the load in kilograms

Area of steel wire = π * r^2, where π= 3.14, r = 1.2/2 = 0.6mm or 6.0 * 10^-4m

= 3.14 * (6.0 * 10⁻⁴m)^2 = 1.13*10⁻⁶m²

<em>Stress = </em>10m / 1.13*10⁻⁶m²

<em> Strain = extension / original length</em>

= (new length - original length)/original length

= (3.2016 - 3.2000)/3.2000

Strain = 0.0005

Using Young's Modulus = Stress / Strain

Note: 1Pa = 1N/m² ; Young's modulus for steel is 2.0 × 10¹¹ Pa or N/m²

2.0*10¹¹ N/m²= Stress / Strain

2.0*10¹¹ = (10m / 1.13*10⁻⁶) / 0.0005

0.0005 * 2.0*10¹¹  = 10m/1.13*10⁻⁶

10m  = 1.13*10⁻⁶ * 0.0005*2*10¹¹

10m  = 113

m = 11.3 kg

Therefore, the mass, m, of the load = 11.3 Kg

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Answer:

0.0072 m³/s

Explanation:

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A₁ = πr₁² = π (0.06/2)² = 0.0028278 m²

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500 ( 1 - 0.3161 ) v₂²  = (31.0 - 24 ) × 10³ Pa

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v₂ = √ 20.472 = 4.525 m/s

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3 years ago
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Answer:

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Explanation:

From collisions in momentum, we can establish the formula required here which is;

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v1 = -1 m/s (negative due to the negative direction it is approaching)

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