Answer:
The mass, m, of the load = 11.3 Kg
Explanation:
Young's Modulus = Stress / Strain
<em>Stress = Force / Area
</em>
Force = mass,m * acceleration due to gravity,g
assuming g = 10ms⁻²
therefore, Force = 10m
m is mass of the load in kilograms
Area of steel wire = π * r^2, where π= 3.14, r = 1.2/2 = 0.6mm or 6.0 * 10^-4m
= 3.14 * (6.0 * 10⁻⁴m)^2 = 1.13*10⁻⁶m²
<em>Stress = </em>10m / 1.13*10⁻⁶m²
<em>
Strain = extension / original length</em>
= (new length - original length)/original length
= (3.2016 - 3.2000)/3.2000
Strain = 0.0005
Using Young's Modulus = Stress / Strain
Note: 1Pa = 1N/m²
; Young's modulus for steel is 2.0 × 10¹¹ Pa or N/m²
2.0*10¹¹ N/m²= Stress / Strain
2.0*10¹¹ = (10m / 1.13*10⁻⁶) / 0.0005
0.0005 * 2.0*10¹¹ = 10m/1.13*10⁻⁶
10m = 1.13*10⁻⁶ * 0.0005*2*10¹¹
10m = 113
m = 11.3 kg
Therefore, the mass, m, of the load = 11.3 Kg
