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3 years ago

5

Despite the fact that the partial pressure difference is so much smaller for co2, why is there as much co2 exchanged between the

alveoli and blood as there is o2, ?

1 answer:

Snezhnost [94]3 years ago

7 0

This is due to the solubility of CO₂ in blood is more than the solubility of Oxygen in blood

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The smallest unit which maintains the physical properties of a compound is a(n _____. atom element molecule alloythe smallest un

LuckyWell [14K]

The answer that would best complete the given statement above is the term ATOM. <span>The smallest unit which maintains the physical properties of a compound is an ATOM. But for a compound, it would be molecule. Hope this answers your question.</span>

5 0

4 years ago

Select all that apply. Any element can always be identified by its _____.

Gala2k [10]

The answer is c. number of protons and d. atomic number. The proton number can identify an element. And also the atomic number is equal to the number of protons.

4 0

3 years ago

Read 2 more answers

For the gaseous reaction of carbon monoxide and chlorine to form phosgene (COCl₂):(b) Assuming that ΔS° and ΔH° change little wi

maksim [4K]

ΔG° at 450. K is -198.86kJ/mol

The following is the relationship between ΔG°, ΔH, and ΔS°:

ΔH-T ΔS = ΔG

where ΔG represents the common Gibbs free energy.

the enthalpy change, ΔH

The temperature in kelvin is T.

Entropy change is ΔS.

ΔG° = -206 kJ/mol

ΔH° equals -220 kJ/mol

T = 298 K

Using the formula, we obtain:

-220kJ/mol -T ΔS° = -206kJ/mol

220 kJ/mol +206 kJ/mol =T ΔS°.

-T ΔS = 14 kJ/mol

for ΔS-14/298

ΔS=0.047 kJ/mol.K

450K for the temperature Completing a formula with values

ΔG° = (450K)(-0.047kJ/mol)-220kJ/mol

ΔG° = -220 kJ/mol + 21.14 kJ/mol.

ΔG°=198.86 kJ/mol

Learn more about ΔG° here:

brainly.com/question/17214066

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7 0

2 years ago

List down the observations made by Rutherford during the gold foil experiment.

Travka [436]

Answer:

1) The volume occupied by an atom is composed of mainly empty space

2) Atoms have a very small, relatively dense, central nucleus that is positively charged

3) The region around the nucleus of an atom are orbited by negatively charged electrons in a the same fashion planets orbit around the Sun.

Explanation:

The selection of gold for the gold foil experiment was due to its ability to be rolled into extremely thin sheets such that it was expected for alpha particle to perforate or pass through the foil.

7 0

3 years ago

The principal source of sulfur on earth is deposits of free sulfur occurring mainly in volcanically Active regions. The offer wa

aivan3 [116]

Answer:

1.18x10⁸L of SO₂ and 2.36x10⁸L of H₂S

Explanation:

The balanced reaction is:

8SO₂(g) + 16H₂S(g) → 16H₂O(l) + 3S₈(s)

To solve this question we must find the moles of S₈ in 4.50x10⁵kg. With these moles and the reaction we can find the moles of SO₂ needed to react (Twice these moles = Moles Of H₂S needed). Using PV = nRT we can find the volume of the gas required:

<em>Moles S₈ - molar mass: 256.52g/mol-</em>

4.50x10⁵kg = 4.50x10⁸g * (1mol / 256.52g) =

1.75x10⁶ moles S₈

<em>Moles SO₂:</em>

1.75x10⁶ moles S₈ * (8mol SO₂ / 3mol S₈) = 4.68x10⁶ moles SO₂

<em>Moles H₂S:</em>

4.68x10⁶ moles SO₂ * 2 = 9.36x10⁶ moles H₂S

The volume could be obtained as follows:

PV = nRT

V = nRT / P

<em>V is volume in liters</em>

<em>n are moles: 4.68x10⁶ moles SO₂ and 9.36x10⁶ moles H₂S</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is absolute temperature = 22°C + 273.15 = 295.15K</em>

<em>P is pressure = 0.961atm</em>

<em />

Replacing:

Volume SO₂ and H₂S:

4.68x10⁶ moles * 0.082atmL/molK * 295.15K / 0.961atm =

<h3>1.18x10⁸L of SO₂ and:</h3>

<em>9.36x10⁶ moles H₂S</em> * 0.082atmL/molK * 295.15K / 0.961atm =

<h3>2.36x10⁸L of H₂S</h3>

5 0

3 years ago