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2 years ago

Name all of the steps on the Physical Activity Pyramid?

Physics

1 answer:

iogann1982 [59]2 years ago

3 0

Answer:

The steps are:-

Moderate physical activity
Vigorous aerobics
Vigorous sport and recreation
Muscle fitness exercise
Flexibility exercise
Avoiding inactivity
Balancing energy

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Una bala calibre se deja caer desde el piso 84 (a una altura de 250 metros) La bala tiene una masa de 0,008 kg. ¿A qué velocidad

Vitek1552 [10]

Answer:

Explanation:

5 0

3 years ago

Which best describes a circuit in series?

Tpy6a [65]

A circuit which only has one path for current to follow

6 0

3 years ago

In the two-slit experiment, monochromatic light of wavelength 600 nm passes through a 19) pair of slits separated by 2.20 x 10-5

kumpel [21]

Explanation:

It is given that,

Wavelength of monochromatic light, $\lambda=600\ nm=6\times 10^{-7}\ m$

Slits separation, $d=2.2\times 10^{-5}\ m$

(a) We need to find the angle corresponding to the first bright fringe. For bright fringe the equation is given as :

$d\ sin\theta=n\lambda$ , n = 1

$\theta=sin^{-1}(\dfrac{\lambda}{d})$

$\theta=sin^{-1}(\dfrac{6\times 10^{-7}}{2.2\times 10^{-5}})$

$\theta=1.56^{\circ}$

(b) We need to find the angle corresponding to the second dark fringe, n = 1

So, $d\ sin\theta=(n+\dfrac{1}{2})\lambda$

$sin\theta=\dfrac{3\lambda}{2d}$

$\theta=sin^{-1}(\dfrac{3\lambda}{2d})$

$\theta=sin^{-1}(\dfrac{3\times 6\times 10^{-7}}{2\times 2.2\times 10^{-5}})$

$\theta=2.34^{\circ}$

Hence, this is the required solution.

4 0

3 years ago

Cyclotrons are widely used in nuclear medicine for producing short-lived radioactive isotopes. These cyclotrons typically accele

lyudmila [28]

Answer:

Part a)

$v = 3.16 \times 10^7 m/s$

Part b)

r = 0.166 m

Explanation:

Part a)

As we know that the energy of the Hydride ion is given as

$E = 5 MeV$

here we have

$\frac{1}{2}mv^2 = 5\times 10^6(1.6 \times 10^{-19})$

also we know that

$m = 1.6 \times 10^{-27} kg$

now we have

$v = \sqrt{\frac{2 \times 5 \times 10^6(1.6 \times 10^{-19}}{1.6\times 10^{-27}}$

$v = 3.16 \times 10^7 m/s$

Part b)

As we know that magnetic force on the charge is centripetal force

so we have

$qvB = \frac{mv^2}{r}$

so we have

$r = \frac{mv}{qB}$

so we have

$r = \frac{1.6 \times 10^{-27}(3.16 \times 10^7)}{(1.6 \times 10^{-19}) 1.9}$

$r = 0.166 m$

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3 years ago

Imagine you are in an open field where two loudspeakers are set up and connected to the same amplifier so that they emit sound w

WINSTONCH [101]

Answer:

Explanation:

frequency of sound waves = 688 Hz

wavelength = 344 / 688 = .5 m

The problem is based on interference of sound waves

For the observer , path difference of sound waves reaching his ear

= 3.5 - 3.00

.5 m

= wavelength

Path difference is equal to wavelength so there will be constructive interference and hence louder sound will be heard by the listener than normal sound as sound waves interfere constructively.

6 0

3 years ago