The numbers are:  36 and 11 .
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Explanation:
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Let us represent the TWO (2) numbers with the variables; 
         "x" and "y" .
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     x + y = 47 .
     y − x = 25.
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Since:  " y − x = 25 " ;
Solve for "y" in terms of "x" ;
  y − x = 25  ;
Add "x" to each side of the equation:
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   y − x + x  = 25 + x  ;
to get:
   y = 25 + x .
Now, since:
  x + y = 47 ; 
Plug in "(25 + x)" as a substitution for "y"; to solve for "x" :
x + (25 + x) = 47  ;
x + 25 + x + 47 ;
2x + 25 = 47 ;
Subtract "25" from each side of the equation:
2x + 25 − 25 = 47 − 25 ;
2x  = 22  ;
Divide EACH SIDE of the equation by "2" ; 
 to isolate "x" on one side of the equation; and to solve for "x" ; 
  
2x / 2 = 22 / 2 ;
    x = 11 ;
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x + y = 47<span> ;
</span>Plug in "11" for "x" into the equation ; to solve for "y" ;
11 + y = 47 ;
Subtract "11" from EACH SIDE of the equation;
  to isolate "y" on one side of the equation; and to solve for "y" ;
 11 + y − 11 =  47 − 11  ;
            y = 36 .
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So:  x = 11 , y = 36 ;
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 Let us check our work:
y − x = 25 ; 
36 − 11 =? 25 ?  Yes!
x + y = 47 ; 
36 + 11 =? 47 ? Yes!
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The numbers are:  36 and 11 .
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Answer:
I'm getting stuck by 

Sorry I can't help you out, if you find the answer through FP lmk
 
        
             
        
        
        
Answer:
B) 5x^2
Step-by-step explanation:

We can divide 50 by 2, we get 25 and we can cancel out x from x^5.
Therefore, we get

= √25x^4
When we take the square root of 25, we get 5 and √x^4 = x^2.
Taking the square root, we get
= 5x^2
Answer: B) 5x^2
Thank you.
 
        
             
        
        
        
Answer:
Thanks for the points- but im a duma$s
Step-by-step explanation: