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evablogger [386]
3 years ago
15

Twenty six million gallons per day of wastewater with a DO of 1.00 mg/L is discharged into a river with a DO of 6.00 mg/L. If th

e flow rate of the river is 165 x 106 gal/d and saturation value of dissolved oxygen is 9.17 mg/L, what is the oxygen deficit he two flows? (0 Points)
Engineering
1 answer:
laiz [17]3 years ago
8 0

Answer:

oxygen deficit = 3.851 mg/L

Explanation:

given data

flow rate of the river=  165 × 10^{6} gal/d

saturation value of dissolved oxygen = 9.17 mg/L

to find out

oxygen deficit he two flows

solution

we will apply here formula for dissolved oxygen content after dilution is

Do mix = \frac{Qw*(Do)w +Qr*(Do)r}{Qw+Qr}     ..........................1

here Qw is rate of flow of waste water  i.e 26 ×10^{6} gal/d

(Do)w is Do of waste waster i.e 1 mg/L

Qr is aret of flow of river i.e 165 ×10^{6} gal/d

(Do)r is do of river water i.e 6 mg/L

so put all value in equation 1 we get

Do mix = \frac{26*10^6*1 +165*10^6*6}{(26+165)10^6}

solve we get

Do mix = 5.319 mg/L

so

oxygen deficit =  saturation oxygen - (Do) mix     ..............2

oxygen deficit = 9.17 - 5.319

oxygen deficit = 3.851 mg/L

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