Answer:
oxygen deficit = 3.851 mg/L
Explanation:
given data
flow rate of the river= 165 × gal/d
saturation value of dissolved oxygen = 9.17 mg/L
to find out
oxygen deficit he two flows
solution
we will apply here formula for dissolved oxygen content after dilution is
Do mix = ..........................1
here Qw is rate of flow of waste water i.e 26 × gal/d
(Do)w is Do of waste waster i.e 1 mg/L
Qr is aret of flow of river i.e 165 × gal/d
(Do)r is do of river water i.e 6 mg/L
so put all value in equation 1 we get
Do mix =
solve we get
Do mix = 5.319 mg/L
so
oxygen deficit = saturation oxygen - (Do) mix ..............2
oxygen deficit = 9.17 - 5.319
oxygen deficit = 3.851 mg/L