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Helga [31]
4 years ago
10

Can anybody teach me how to make an app with flask and pygame together?​

Engineering
1 answer:
sweet [91]4 years ago
8 0

Answer:

no :-(

Explanation:

Are you sure these technologies fit together?

As I understand it, flask is a library to write web services using python. It will essentially serve HTML pages and perhaps REST interfaces?

Pygame is a local machine abstraction layer to graphics and other i/o. I don't think it will run in a browser.

What is your plan?

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what do we call a landslide in which fine-grained soil moves cohesively but with extensive internal shearing?
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It is called an earth flow
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Which regulations are related to guard rail height and dimensions and uniformity of stairs?
galina1969 [7]

Answer:

C.

structural safety

Explanation:

Guards protecting floor surfaces must be 36 inches in height, while guards for stairs must be 34 inches in height measured vertically from the tread nosing. A guard may also serve as the required handrail (34 to 38 inches high) provided the top rail meets the requirements for grip size.

4 0
3 years ago
Read 2 more answers
Calculate the current in the 8-W resistor of Figure below by using Thevenin’s theorem. What will be its value of connections of
kvv77 [185]

solution from c hegg. hope it helps. see photos explanation

7 0
3 years ago
4. Which type of duct undergoes more rigorous testing before it's labeled?
Alenkasestr [34]

Answer:

Flexible duct

Explanation:

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7 0
3 years ago
7.4 A pretimed four-timing-stage signal has critical lane group flow rates for the first three timing stages of 200, 187, and 21
Irina18 [472]

Answer:

16 seconds

Explanation:

Given:

C = 60

L = 4 seconds each = 4*4 =16

In this problem, the first 3 timing stages are given as:

200, 187, and 210 veh/h.

We are to find the estimated effective green time of the fourth timing stage. The formula for the estimated effective green time is:

g = (\frac{v}{s}) (\frac{C}{X})

Let's first find the fourth stage critical lane group ratio \frac{v}{s} , using the formula:

C = \frac{1.5L +5}{1 - ( \frac{200}{1800} + \frac{187}{1800} + \frac{210}{1800}) + ( \frac{v}{s})}

60 = \frac{1.5*16 + 5}{1 - ( \frac{200}{1800} + \frac{187}{1800} + \frac{210}{1800}) + ( \frac{v}{s})}

60 = \frac{24+5}{1 - (0.332 + ( \frac{v}{s}))}

Solving for (\frac{v}{s}), we have:

(\frac{v}{s}) = 0.185

Let's also calculate the volume capacity ratio X,

X = (\frac{200}{1800} + \frac{187}{1800} + \frac{210}{1800} + 0.185)(\frac{60}{60-16}

X = 0.704

For the the estimated effective green time of the fourth timing stage, we have:

g_4 = (\frac{v}{s}) (\frac{C}{X})

Substituting figures in the equation, we now have:

g_4 = (0.185) (\frac{60}{0.704})

g_4 = 15.78 seconds

15.78 ≈ 16 seconds

The estimated effective green time of the fourth timing stage is 16 seconds

8 0
3 years ago
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