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pantera1 [17]
3 years ago
12

Marcelo es muy bueno resolviendo adivinanzas y acertijos. Por eso, estaba totalmente disgustado cuando se dio cuenta de que no e

ra capaz de resolver un acertijo muy conocido y que no es tan difícil de resolver.
Pero no se dejó vencer: se dirigió a una pizarra cercana y realizó el diagrama de la imagen adjunta (ver imagen).
Cuando terminó, dio un paso para atrás y dijo: “Bueno, ahora la solución es realmente obvia”. Y realmente lo era. La pregunta para ti es: ¿De qué acertijo se trata?

Engineering
1 answer:
makvit [3.9K]3 years ago
6 0
English please I can’t understand
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A rigid, well-insulated tank of volume 0.9 m is initially evacuated. At time t = 0, air from the surroundings at 1 bar, 27°C beg
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Answer:

\dot{w}= -0.303 KW

Explanation:

This is the case of unsteady flow process because properties are changing with time.

From first law of thermodynamics for unsteady flow process

\dfrac{dU}{dt}=\dot{m_i}h_i+\dot{Q}-\dot{m_e}h_i+\dot{w}

Given that tank is insulated so\dot{Q}=0 and no mass is leaving so

\dot{m_e}=0

\int dU=\int \dot{m_i}h_i\ dt-\int \dot{w}\ dt

m_2u_2-m_1u_1=(m_2-m_1)h_i- \dot{w}\Delta t

Mass conservation m_2-m_1=m_e-m_i

m_1,m_2 is the initial and final mass in the system respectively.

Initially tank is evacuated so m_1=0

We know that for air u=C_vT ,h=C_p T,P_2v_2=m_2RT_2

m_2=0.42 kg

So now putting values

0.42 \times 0.71 \times 730=0.42\times 1.005\times 300- \dot{w} \times 300

\dot{w}= -0.303 KW

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