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ivolga24 [154]
3 years ago
5

In RSA Digital Signature, Suppose Bob wants to send a signed message (x = 4) to Alice. The first steps are exactly t eps are exa

ctly the same as it is done for an RSA encryption: Bob computes his RSA parameters and sends the public key to Alice. We know p = 3, q=11, and bob choose e=3. (Hint: We learn RSA algorithm and key generation in Week 7) (1) What is the public key pair Bob sends to Alice? (2) What is the value of signature s? (3) What is the value of verkpubA(x,s)? Show all intermediate steps clearly.
Engineering
1 answer:
Luda [366]3 years ago
4 0

Answer:

what r u on

Explanation:

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Java Programming: Loops and Conditionals
velikii [3]

Answer:

  1. import java.util.Scanner;
  2. import java.util.Random;
  3. public class Main {
  4.    public static void main(String[] args) {
  5.        Scanner input = new Scanner(System.in);
  6.        Random rand = new Random();
  7.        System.out.print("Enter number of questions you wish to practice: ");
  8.        int n = input.nextInt();
  9.        int i = 1;
  10.        while(i <= n){
  11.            int num1 = 1 + rand.nextInt(10);
  12.            int num2 = 1 + rand.nextInt(10);
  13.            int answer = num1 * num2;
  14.            System.out.print("Question " + i + ": " + num1 + " x " + num2 + " = ");
  15.            int response = input.nextInt();
  16.            if(response == answer){
  17.                System.out.println("Correct answer!");
  18.            }
  19.            else{
  20.                System.out.println("Wrong answer. It should be " + answer);
  21.            }
  22.            i++;
  23.        }
  24.    }
  25. }

Explanation:

Firstly, we import Scanner and Random classes (Line 1-2) as we need to get user input for number of questions and generate random number in each question.

Next, create a Scanner and Random object (Line 7-8).  Prompt user to input number of question and get the input using the Scanner object (Line 10-11).

Next create a while loop and set the condition to loop for n number of times (based on number of questions) (Line 14). In the loop, use Random object nextInt method to generate two integers between 1 -10 (Line 15-16). Prompt user to input an answer using the Scanner object (Line 18-19). If the response is matched with answer print a correct message (Line 21-22) other wise inform user they write a wrong answer and show the correct answer (Line 24-25).

8 0
4 years ago
2. What is the charge, expressed in micro coulombs on two equally and similarly charges spheres placed in air with their centres
9966 [12]

Answer:

q = 0.1086 micro Coulombs

Explanation:

By Coulombs law, we have;

F =k \times  \dfrac{ q_1 \times q_2}{r^2}

Where;

F = The electric force = 120 mgm

q₁ and q₂ = Charge

r = The separating distance = 30 cm = 0.3 m

k = 8.9876×10⁹ kg·m³/(s²·C²)

Where, q₁ and q₂, we have;

F =k \times  \dfrac{ q^2}{r^2}

Whereby the force is the force of 120 milligram mass, we have;

0.00012 × 9.81 = 000011772 N

q = \sqrt{ \dfrac{ F\times r^2}{k}}

Substituting the values, we have;

q = \sqrt{ \dfrac{ 000011772 \times (0.3)^2}{8.9876 \times 10^9}} = 1.086 \times 10 ^{-7} \ Coulombs

q = 0.1086 micro Coulombs.

5 0
3 years ago
Convert 250 lb·ft to N.m. Express your answer using three significant figures.
vfiekz [6]

Answer:

It will be equivalent to 338.95 N-m

Explanation:

We have to convert 250 lb-ft to N-m

We know that 1 lb = 4.45 N

So foe converting from lb to N we have to multiply with 4.45

So 250 lb = 250×4.45 =125 N

And we know that 1 feet = 0.3048 meter

Now we have to convert 250 lb-ft to N-m

So 250lb-ft=250\times 4.45N\times 0.348M=338.95N-m

So 250 lb-ft = 338.95 N-m

6 0
3 years ago
Our rule-of-thumb for presenting final results is to round to three significant digits or four if the first digit is a one. By t
olga_2 [115]

Answer:

To four significant digits = 2097 psi

Explanation:

<u>Applying the rule of thumb </u>

σ = Mc/I  ---- ( 1 )

M = 1835 Ibf in ,  I/c = 0.875 in^3

∴ c/l = 1 / 0.875 = 1.1429

back to equation 1

σ = 1835 * 1.1429 = 2097.2215 psi

To four significant digits = 2097 psi

4 0
3 years ago
10 litres of an ideal gas at 27°C and 12atm pressure is isothermally and reversibly expanded to a final pressure of 3atm.Calcula
Sliva [168]

Known :

V1 = 10 L

T1 = 27°C

P1 = 12 atm

P2 = 3 atm

Solution :

Work done in the process

W = P1 • V1 ln (P1 / P2)

W = (12 atm) • (10 L) ln (12 / 3)

W = 166.35 L • atm

W = 168.55 kJ

7 0
2 years ago
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