Question

What would the current be for a circuit that has a voltage of 0.8 V and a resistance of 0.01 Q?

Answer 1

Answer:

80 A

Explanation:

Hi there!

Ohm's law states that $V=IR$ where V is the voltage, I is the current and R is the resistance.

Plug the given information into Ohm's law (V=0.8, R=0.01) and solve for I

$V=IR\\0.8=I(0.01)$

Divide both sides by  0.01 to isolate I

$0.8=I(0.01)\\\frac{0.8}{0.01}= \frac{I(0.01)}{0.01} \\80=I$

Therefore, the current for this circuit would be 80 A.

I hope this helps!