Hi!
We are given the information found in the picture below.
Note: The directions aren't correct, but the triangle works for this problem.
The "direct path" is the hypotenuse of this triangle.
To find this, we use the Pythagorean Theorem, where and
are 2 legs of the triangle, and
is the hypotenuse, aka the longest side of any triangle:
We know and
and want
Therefore, is approximately
Answer:
Part 1:
The solution set of the system of equations is x = 1, y = 1
Part 2:
The solution set is x = 1, y = 1
Part 3:
The similarity of the system of equations in Parts 1 and 2 is that they have the same solution set
The difference of the system of equations in Parts 1 and 2 is that they are arranged differently
Step-by-step explanation:
Part 1:
The system of equation is given as follows;
2·x + y = 3...(1)
x = 2·y - 1...(2)
The above system of equations can be written in terms of the variable, y, as follows;
For equation (1), we have;
y = 3 - 2·x
For equation (2), we have;
y = (x + 1)/2
From the attached graph created with Microsoft Excel, we have;
The solution set (the point of intersection) of the system of equations is x = 1, y = 1
To accurately find the common solution, we have;
(x + 1)/2 = 3 - 2·x
x + 1 = 2·(3 - 2·x) = 6 - 4·x
x + 1 = 6 - 4·x
x + 4·x = 6 - 1
5·x = 5
x = 5/5 = 1
x = 1
Therefore, y = 3 - 2·x = 3 - 2× 1 = 1, at the common solution
Part 2:
y = -2x + 3
x - 2y = -1
∴ x = 2y -1
y = -2(2y -1) + 3
y = -4y + 2 + 3
5y = 5
y = 1
x = 2y - 1 = 2 - 1 = 1
x = 1
The solution set is x = 1, y = 1
Part 3
The system of equations are similar in terms of their solution
The system of equations are different in terms of their arrangement
