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3 years ago

Explain why particles in a gas are free to move far away from each other.

2 answers:

7 0

The reason that particles of gas are able to move freely around is because most gases in themselves have week bonds to each other and even so with those bonds the gas has large amounts of energy to break those such bonds. Ex: When you boil water, what do you use to boil it? Heat, and heat is energy you add heat to the water energizing the water allowing the water to jump up and away form it turning it into gas, but since it is now gas and charged it has free roam.<span />

Mamont248 [21]3 years ago

4 0

The particles that are in the gas are packed loosely and has no definite shape or volume

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Describe the motion of an object that has an acceleration of 0m/s2

solong [7]

Zero acceleration means the object's velocity is not changing.
So the object is moving in a straight line, at a constant speed
that could be anything (including zero) as long as it's constant.

6 0

3 years ago

A source charge of 3 µC generates an electric field of 2.86 × 105 N/C at the location of a test charge. Using k = 8.99 × 109N.m^

Nataliya [291]

Variables:

Source charge, Q = 3 micro C = 3 * 10^ - 6 C

E = electric field = 2.86 * 10 ^5 N/C

K = 8.99 * 10^9 N * m^2 / C

d = distance = ?

Formula:

E = K * Q / (d^2) => d^2 = K * Q / E

=> d^2 = 8.99 * 10^9 N * m^2 / C * 3 * 10^ -6 C / (2.86 * 10^ 5 N/C)

d^2 = 9.43 * 10 ^ -2 m^2

=> d = 3.07 * 10^-1 m

Answer: 0.307 m

Note: it is a long distance due to the Electric field is very low

7 0

3 years ago

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What is the amount of work done when JoAnne throws a baseball 2 meters at a force of 40

sergiy2304 [10]

Answer:

Amount of work done by Joanne = 80 joule

Explanation:

Given:

Displacement of ball = 2 meters

Force applied = 40 newtons

Find:

Amount of work done by Joanne

Computation;

Work done = Force applied x Displacement

Amount of work done by Joanne = Force applied x Displacement of ball

Amount of work done by Joanne = 40 x 2

Amount of work done by Joanne = 80 joule

5 0

3 years ago

on takeoff, the propellers on a uav (unmanned aerial vehicle) increase their angular velocity from rest at a rate of ω = (25.0t)

Rudik [331]

Hi there!

a)
We can find the angular velocity at t = 2.0 s by plugging in this value into the equation.

$\omega (t) = 25.0t \\\\\omega (2) = 25.0(2) = \boxed{50.0 \frac{rad}{s}}$

The angular acceleration is the derivative of the angular velocity, so:
$\alpha (t) = \frac{d\omega}{dt} (25.0t) = 25.0$

Thus, the angular acceleration is a <u>constant 25 rad/s².</u>

7 0

2 years ago

a 800 kg roller coaster cart is accelerated by a constant net force over a distance of 10 meters, as shown in the graph below: d

devlian [24]

Answer:

vf = 22.36[m/s]

Explanation:

First we must understand the data given in the problem:

m = mass = 800 [kg]

F = force = 20000[N]

dx = displacement = 10[m]

From newton's second we know that the sum of forces must be equal to the product of mass by acceleration.

$F = m*a\\20000 = 800*a\\a = 20000/800\\a = 25 [m/s^2]$

With the calculated acceleration, we can use the kinematics equations.

$v_{f} ^{2} =v_{o} ^{2}+2*a*dx\\ v_{o} = initial velocity = 0\\a = acceleration = 25[m/s^2]\\dx= displacement = 10[m]\\$

The key to using this equation is to clarify that the initial velocity is zero since the body is at rest, otherwise the initial velocity would be an initial data.

$v_{f} =\sqrt{2*25*10} \\v_{f} =22.36[m/s]$

Another way of solving this problem is by means of the definition of work and kinetic energy, where work is defined as the product of the force by the distance.

W =F*d

W = 20000*10

W = 200000[J]

Kinetic energy is equal to work, therefore the value calculated above is equal to:

$E_{k}=W =0.5*m*v_{f}^{2} \\200000=0.5*800*v_{f}^{2}\\v_{f}=\sqrt{\frac{200000}{0.5*800} } \\v_{f}=22.36[m/s]$

7 0

3 years ago

Read 2 more answers