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saw5 [17]
2 years ago
12

The two rods are now firmly attached together as in Figure 2.

Physics
1 answer:
MakcuM [25]2 years ago
4 0

Thermal equilibrium is attained and the both rods are now at the same temperature.

<h3>What is thermal equilibrium?</h3>

Two bodies are said to have attained thermal equilibrium when the two bodies at the same temperature. It should be known that when two rods are firmly attached to each other heat flows from one rod to another.

As such, after some time, thermal equilibrium is attained and the both rods are now at the same temperature.

Learn more about thermal equilibrium:brainly.com/question/2637015

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Whats the velocity of a ball falling with 100joules of kinetic energy and a mass of 2 kilograms?
nlexa [21]
Short answer: v = 10 m/s
Comment
This is just an application of KE = 1/2 m v^2
Givens
KE = 100 Joules
m = 2 kg
v = ???

Formula
KE = 1/2 m v^2

Substitution and Solve
100 = 1/2 * 2 * v^2
100 = v^2 Take the square root of both sides.
sqrt(100) = sqrt(v^2)
v = 10 m/s

Comment
There is no KE unless v > 0. 
You may have  PE when v = 0, but not KE.
5 0
3 years ago
What is kinematics?<br>explain!!~​<br><br>thankyou ~
Hatshy [7]

Answer:

<u>Kinematics:-</u>

  • Branch of mechanics concerned
  • Features of motion in an object
  • Causes and effects of motions

Hope it helps!

6 0
3 years ago
Read 2 more answers
Two magnets are placed near each other on a space station orbiting Earth.
dimulka [17.4K]

Answer: A. They will be repelled because they are in each other's magnetic

field.

Explanation: Apex and gravity and electrical don't have effect on magnets magnetic field.

5 0
3 years ago
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WHAT SHOULD I NAME MY DEAD RAT?
olga_2 [115]

Answer:

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6 0
3 years ago
You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this state
posledela

Answer:

a)  y₂ = 49.1 m ,    t = 1.02 s , b)   y = 49.1 m , t= 1.02 s

Explanation:

a) We will solve this problem with the missile launch kinematic equations, to find the maximum height, at this point the vertical speed is zero

            v_{y}² = v_{oy}² - 2 g (y –yo)

The origin of the coordinate system is on the floor and the ball is thrown from a height

           y-yo = v_{oy}² /2 g&#10;            y- 0 = 10.0²/2 9.8&#10;            y - 0 = 5.10 m&#10;            &#10;The height from the ground is the height that rises from the reference system plus the depth of the ground from the reference system&#10;             y₂ = 5.1 + 44&#10;             y₂ = 49.1 m&#10;Let's use the other equation to find the time&#10;              [tex]v_{y} = v_{oy} - g t

              t = v_{oy} / g

              t = 10 / 9.8

              t = 1.02 s

b) the maximum height

            y- 44.0 = v_{y}² / 2 g

            y - 44.0 = 5.1

            y = 5.1 +44.0

            y = 49.1 m

The time is the same because it does not depend on the initial height

              t = 1.02 s

7 0
3 years ago
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