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dimaraw [331]
2 years ago
7

A sample of air has a volume of 140 mL 0.980 atm. At what pressure will its final volume be 50.0 mL at constant temperature?

Chemistry
1 answer:
bogdanovich [222]2 years ago
4 0

Answer:

The new pressure is 2, 74 atm

Explanation:

We apply Boyle Mariotte's law, where for a given mass of gas at constant temperature, the pressure and volume vary inversely proportionally:        P1xV1 = P2xV2  P2=( P1 x V1)/V2     1 L-----1000L--->( 140ml/1000ml)x1L=0,140 L

(50ml/1000ml)x 1L =0,050L

P2= (0,980 atm x 0,140 L)/0,050L= 2, 744 atm

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Can I get help with this, please!!
kondor19780726 [428]

Pressure in the submarine when the temperature is changed to 293 K is 108.9 K Pa

Explanation:

Pressure in the submarine = 108.9 kPa

Volume, V = 2.4 * 10^5 L

Pressure, P = 116k Pa

Temperature, T = 312 K

Ideal gas law: PV = nRT  or  n = PV / RT

So, moles of gas, n =116 KPa * 2.4 * 10 ^5L / 8.314 LK Pa K^-1 *312 K

= 1.073 *10^4 mol

when temperature is changed to 293K,

PV = nRT  or P = nRT / V

=1.073 *10^4 mol *8.314 LK Pa mol^-1 K^-1 *293 K / 2.4*10^5L

=108.9 K Pa

Pressure in the submarine when the temperature is changed to 293 K is 108.9 K Pa

8 0
2 years ago
Which of these pathogens can be killed by antibiotics?
Alisiya [41]

Answer:

it's c.

Explanation:

hope this helps

5 0
3 years ago
What will i observe when i bring the elrctro magnet near to some aluminum clips?
Llana [10]
Hey mate here is ur ans
Basically, Aluminium is paramagnetic and has a very, very slight attraction to a magentic field. We don't notice it.
3 0
3 years ago
What are the carbon (C) and oxygen (O) in carbon dioxide (CO2)?
Fynjy0 [20]
A. Atoms. Because I learned this in 6th grade.
6 0
2 years ago
The density of ethanol is 0.789 g/mL. If you need 460.0 g of ethanol for an experiment, how many milliliters would you measure o
4vir4ik [10]

Answer:

The volume is 583.02 mL

Explanation:

Given that the density is:-

\rho=0.789\ g/mL

The mass, m=460.0\ g

The expression for the calculation of density is shown below as:-

\rho=\frac{m}{V}

Using the above expression to calculate the volume as:-

V=\frac{m}{\rho}

Applying the values to calculate the volume as:-

V=\frac{460.0\ g}{0.789\ g/mL}=583.02\ mL

<u>The volume is 583.02 mL.</u>

3 0
3 years ago
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