A sample of air has a volume of 140 mL 0.980 atm. At what pressure will its final volume be 50.0 mL at constant temperature?
1 answer:
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2074.74 kg is the mass of siderite in which 1x10^3 kg of iron is present.
Explanation:
Mass of iron is given as 1x10^3 Kg
mass of iron in siderite FeCO3 can be known
number of moles in 1x10^3 Kg iron is calculated by the formula.
number of moles =
atomic weight of iron is 55.84
number of moles =
n= 17908.309 moles of iron in 1000 kg
1 mole of FeCO3 has 1 mole of Fe
x moles of FeCO3 will have moles
=
x = 17908.309 moles of FeCO3 is there.
so mass can be calculated as number of moles x molar mass of one mole of the substance. (molar mass of siderite is 115.854 grams/mole)
17908.309 x 115.854
= 2074749.230 grams of siderite
(the molar mass is converted to kg/mole as the mass of iron is given by kg.
0.1158 kg is the molar mass of siderite)
2074749.230 grams of siderite is converted to kilogram
2074.74 kg is the mass of siderite in which 1x10^3 kg of iron is present.