Theresa creates an experiment where she mixes two red-colored substances together in a container and observes the solution slowl
2 answers:
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<u>Answer:</u> The new pressure will be 101.46 kPa.
<u>Explanation:</u>
To calculate the new pressure, we use the equation given by Gay-Lussac Law. This law states that pressure is directly proportional to the temperature of the gas at constant volume.
The equation given by this law is:
where,
are initial pressure and temperature.
are final pressure and temperature.
We are given:
By using conversion factor:
Putting values in above equation, we get:
Hence, the new pressure will be 101.46 kPa.
Answer:
O₂; KCl; 33.3
Explanation:
We are given the moles of two reactants, so this is a limiting reactant problem.
We know that we will need moles, so, lets assemble all the data in one place.
2KCl + 3O₂ ⟶ 2KClO₃
n/mol: 100.0 100.0
1. Identify the limiting reactant
(a) Calculate the moles of KClO₃ that can be formed from each reactant
(i)From KCl
(ii) From O₂
O₂ is the limiting reactant, because it forms fewer moles of the KClO₃.
KClO₃ is the excess reactant.
2. Moles of KCl left over
(a) Moles of KCl used
(b) Moles of KCl left over
n = 100.0 mol - 66.67 mol = 33.3 mol