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3 years ago

Which type(s) of matter would need to be separated by chemical methods?

Chemistry

1 answer:

Marta_Voda [28]3 years ago

3 0

Answer:

solids, liquids, gases, or plasma

Explanation:

In chemistry, a chemical substance is a form of matter that has constant chemical composition and characteristic properties. It cannot be separated into components without breaking chemical bonds. Chemical substances can be solids, liquids, gases, or plasma

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At equilibrium at 2500K, [HCl]=0.0625M and [H2]=[Cl2]=0.00450M for the reaction H2+Cl2 ⇌ HCl.

ASHA 777 [7]

Answer:

a. $H_2+Cl_2 \rightleftharpoons 2HCl$

b. K = 192.9

c. Products are favored.

Explanation:

Hello!

a. In this case, according to the unbalanced chemical reaction we need to balance HCl as shown below:

$H_2+Cl_2 \rightleftharpoons 2HCl$

In order to reach 2 hydrogen and chlorine atoms at both sides.

b. Here, given the concentrations at equilibrium and the following equilibrium expression, we have:

$K=\frac{[HCl]^2}{[H_2][Cl_2]}$

Therefore, we plug in the data to obtain:

$K=\frac{(0.0625)^2}{(0.00450)(0.00450)}\\\\K=192.9$

c. Finally, we infer that since K>>1 the forward reaction towards products is favored.

Best regards!

8 0

3 years ago

If a gas had a volume of 6.7 L and started at STP, what would the new pressure be

Phantasy [73]

The new pressure would be = 4.46 atm

<h3>Further explanation</h3>

Given

V₁=6.7 L(at STP, 1 atm 273 K)

V₂=1.5 L

Required

The new pressure

Solution

Boyle's Law

At a constant temperature, the gas volume is inversely proportional to the pressure applied

$\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}$

P₂ = (P₁V₁)/V₂

P₂ = (1 atm x 6.7 L)/1.5 L

P₂ = 4.46 atm

5 0

2 years ago

In a typical reaction, as time passes, the amount of _____ decreases and the amount of _____ increases. Fill in the blank

ELEN [110]

Reactants, products are the answers

8 0

3 years ago

How many atoms are there in 3.559*10^-6 mol of krypton?

algol [13]

Answer:

The answer is

<h2> $2.143 \times {10}^{18} \: \: atoms$ </h2>

Explanation:

To find the number of atoms given the number of moles we use the formula

N = n × L

where

N is the number of entities

n is the number of moles

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

$n = 3.559 \times {10}^{ - 6} \: mol$

Substitute the values into the above formula and solve

That's

<h3> $N = 3.559 \times {10}^{ - 6} \times 6.02 \times {10}^{23} \\ = 2.1425 \times {10}^{18}$ </h3>

We have the final answer as

<h3> $N = 2.143 \times {10}^{18} \: \: atoms$ </h3>

Hope this helps you

3 0

3 years ago

Exercise A mixture of 250 mL of methane, CH4, at 35 °C and 0.55 atm and 750 mL of propane, C3Hg, at 35° C and 1.5 atm, were intr

dalvyx [7]

Explanation:

The given data is as follows.

$V_{1}$ = 250 mL, $V_{2}$ = 750 mL

$T_{1}$ = $35^{o}C$ = 35 + 273 K = 308 K

$T_{2}$ = 35 + 273 K = 308 K

$P_{1}$ = 0.55 atm, $P_{2}$ = 1.5 atm

P = ? , V = 10.0 L

Since, temperature is constant.

So, $P_{1}V_{1} + P_{2}V_{2}$ = PV

Now, putting the given values into the above formula as follows.

$P_{1}V_{1} + P_{2}V_{2}$ = PV

$0.55 atm \times 250 mL + 1.5 atm \times 1.5 atm$ = $P \times 10.0 L$

P = 0.126 atm

As, 1 atm = 760 torr. So, $0.126 atm \times \frac{760 torr}{1 atm}$ = 95.76 torr.

Thus, we can conclude that the final pressure, in torr, of the mixture is 95.76 torr.

8 0

3 years ago