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e-lub [12.9K]
3 years ago
12

Which type of drugs kill pain by blocking impulses at specific receptor sites of the brain and spinal cord? narcotic analgesics

non-narcotic analgesics anti-psychotics tranquilizers
Chemistry
1 answer:
4vir4ik [10]3 years ago
7 0
I believe the correct answer from the choices listed above is the second option. Analgesics are the drugs that kill pain by blocking impulses at specific receptor sites of the brain and spinal cord. Analgesics<span> are drugs that alleviate pain without causing anesthesia. Hope this helps.</span>
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Notice that "SO4" appears in two different places in this chemical equation. SO42− is a polyatomic ion called "sulfate." What nu
vichka [17]

Answer:

3.

Explanation:

Hello,

In this case, it is convenient to write the chemical reaction as:

CaSO_4+AlCl_3\rightarrow CaCl_2+Al_2(SO_4)_3

Which balanced turns out:

3CaSO_4+2AlCl_3\rightarrow 3CaCl_2+Al_2(SO_4)_3

Thus the number that should be in front of the calcium sulfate is 3 in order to balance the reaction.

Best regards.

8 0
3 years ago
In a titration of 47.41 mL of 0.3764 M ammonia with 0.3838 M aqueous nitric acid, what is the pH of the solution when 47.41 mL +
Volgvan

<u>Answer:</u> The pH of the solution is 1.136

<u>Explanation:</u>

To calculate the moles from molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

  • <u>For ammonia:</u>

Molarity of ammonia = 0.3764 M

Volume of ammonia = 47.41 mL = 0.04741 L   (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

0.3764mol/L=\frac{\text{Moles of ammonia}}{0.04741L}\\\\\text{Moles of ammonia}=0.01784mol

  • <u>For nitric acid:</u>

Molarity of nitric acid = 0.3838 M

Volume of ammonia = (47.41 + 10.00) mL = 57.41 mL= 0.05741 L

Putting values in above equation, we get:

0.3838mol/L=\frac{\text{Moles of nitric acid}}{0.05741L}\\\\\text{Moles of nitric acid}=0.02203mol

After the completion of reaction, amount of nitric acid remained = 0.022 - 0.0178 = 0.0042 mol

For the reaction of ammonia with nitric acid, the equation follows:

                       NH_3+HNO_3\rightarrow NH_4NO_3

At t=0             0.0178   0.022

Completion        0     0.0042        0.0178

As, the solution of the reaction is made from strong acid which is nitric acid and the conjugate acid of weak base which is ammonia. So, the pH of the reaction will be based totally on the concentration of nitric acid.

To calculate the pH of the reaction, we use the equation:

pH=-\log[H^+]

where,

[H^+]=\frac{0.0042mol}{0.05741L}=0.0731M

Putting values in above equation, we get:

pH=-\log(0.0731)\\\\pH=1.136

Hence, the pH of the solution is 1.136

8 0
3 years ago
9.11 x 10^3 in standard notation?
Irina18 [472]

Answer:

the right answer is 9110

3 0
3 years ago
Read 2 more answers
What is the pH of a weak acid solution that has an [H+] of 2.1 x 10^-6 M?
yaroslaw [1]

Answer:

5.7 pH

Explanation:

To find pH when given [H+], you use this formula: pH = -log[H+]

-log * 2.1e-6 = 5.6778 = 5.7 pH

3 0
3 years ago
A 15.6 grams of ethanol absorb 868 J as it is heated. The initial temperature is 21.5 degrees Celsius. What is the final tempera
77julia77 [94]
You have to use the equation q=mcΔT and solve for T(final).  
T(final)=(q/mc)+T(initial)
q=the amount of energy absorbed or released (in this case 868J)
m=the mass of the sample (in this case 15.6g)
c= the specific heat capacity of the substance (in this case 2.41 J/g°C)
T(initial)=the initial temperature of the sample (in this case 21.5°C)

When you plug everything in, you should get 44.6°C.
Therefore the final temperature of ethanol is 44.6°C

I hope this helps.  Let me know if anything is unclear.
3 0
3 years ago
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