In a first-order reaction, how does the rate change if the concentration of the reactant decreases to one-third its original val
2 answers:
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Answer:
Hydride ion
Explanation:
You often see the reduction with NADH written as
NADH ⟶ NAD⁺ + H⁺ + 2e⁻
If you think about it, H⁺ + 2e⁻ is equivalent to H:⁻, so we could write the reaction as
NADH ⟶ NAD⁺ + H:⁻
In terms of a mechanism, the dihydropyridine ring of NADH transfers a hydrogen atom with its pair of electrons (a hydride ion) to the substrate and becomes the more stable, aromatic pyridinium ion in NAD⁺.
Answer:
Acid ammonium carbonate // Ammonium bicarbonate.
Explanation:
Hello, a 4 is missing in the fist H, thus:
The presence of the hydrogen between the ammonium and the carbonates characterizes the salt as an acid salt, so you could name it as acid ammonium carbonate or ammonium bicarbonate (similar to the sodium bicarbonate which is .
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