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dmitriy555 [2]
3 years ago
14

Solid aluminum metal and diatomic chlorine gas react spontaneously to form a solid product. Give the balanced chemical equation

(including phases) that describes this reaction.
Chemistry
1 answer:
ValentinkaMS [17]3 years ago
8 0

When solid aluminum metal is reacted with diatomic chlorine gas, solid aluminum chloride is formed. This reaction is an example of synthesis or chemical combination in which two elements, aluminum and chlorine combine to form a new compound aluminum chloride.

Word equation: Aluminum (s)+ Chlorine (g)---> Aluminum chloride(s)

Molecular formula of the product formed is AlCl_{3}.

Therefore the balanced chemical equation representing the reaction of solid aluminum with gaseous dichlorine can be represented as,

2Al(s) + 3Cl_{2}(g)-->2AlCl_{3}(s)

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mass_{oxygen} = \%mass_{oxygen} \times mass_{compound} \\ m = 63\%(100) \\ m = 0.63(100) \\ m = 63 \: grams

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Put the substance in a 25 mL beaker.
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3. no (not a solid)

Explanation:

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Jennie decides to mix the content of her beaker with another lab group to see “the results.” Is this safe why or why not explain
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Answer: no

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An object has a mass of 4 grams and a volume of 2 cm^3.what is the density of the object?
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2.0 grams per cubic centimeter

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Carbon monoxide (CO) reacts with hydrogen (H2) to form methane (CH4) and water (H2O).
Artemon [7]

Answer:

5.9x10^-2 M

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Concentration of CO, [CO] = 0.30 M

Concentration of H2, [H2] = 0.10 M

Concentration of H2O, [H2O] = 0.020 M

Equilibrium constant, K = 3.90

Concentration of CH4, [CH4] =..?

Step 2:

The balanced equation for the reaction. This is given below:

CO(g) + 3H2(g) <=> CH4(g) + H2O(g)

Step 3:

Determination of the concentration of CH4.

The expression for equilibrium constant of the above equation is given below:

K = [CH4] [H2O] / [CO] [H2]^3

3.9 = [CH4] x 0.02/ 0.3 x (0.1)^3

Cross multiply to express in linear form

[CH4] x 0.02= 3.9 x 0.3 x (0.1)^3

Divide both side by 0.02

[CH4] = 3.9 x 0.3 x (0.1)^3 /0.02

[CH4] = 5.9x10^-2 M

Therefore, the equilibrium concentration of CH4 is 5.9x10^-2 M

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3 years ago
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