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Harman [31]
3 years ago
6

Lab: Energy Transfer

Chemistry
1 answer:
tester [92]3 years ago
4 0

2. What procedure did you use to complete the lab?

Outline the steps of the procedure in full sentences.

Section II: Observations and Conclusions

3. What charts, tables, or drawings would clearly show what you have learned in this lab?

Each chart, table, or drawing should have the following items:

a. An appropriate title

b. Appropriate labels

4. If you could repeat the lab and make it better, what would you do differently and why?

There are always ways that labs can be improved. Now that you are a veteran of this lab and have experience with the procedure, offer some advice to the next scientist about what you suggest and why. Your answer should be at least two to three sentences in length.

Writing the Lab Report

Now you will use your answers from the four questions above to write your lab report. Follow the directions below.

Section I: Overview of Lab

Use your answers from questions 1 and 2 (above) as the basis for the first section of your lab report. This section provides your reader with background information about why you conducted this lab and how it was completed. It should be one to two paragraphs in length.

Section II: Observations and Conclusions

Use your answers from questions 3 and 4 (above) as the basis for the second section of your lab report. This section provides your reader with charts, tables, or drawings from the lab. You also need to incorporate your answers to the follow-up questions (from the Student Guide) in your conclusions.

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gogolik [260]

Answer:

m_{HClO_3}=12.7gHClO_3

Explanation:

Hello,

Considering the reaction:

3Cl_2(g)+3H_2O(l)-->5HCl+HClO_3

The molar masses of chlorine and chloric acid are:

M_{Cl_2}=35.45*2=70.9g/mol\\M_{HClO_3}=1+35.45+16*3=84.45g/mol

Now, we develop the stoichiometric relationship to find the mass of chloric acid, considering the molar ratio 3:1 between chlorine and chloric acid, as follows:

m_{HClO_3}=31.6gCl_2*\frac{1molCl_2}{70.9gCl_2} *\frac{1molHClO_3}{3mol Cl_2} *\frac{85.45g HClO_3}{1mol HClO_3} \\m_{HClO_3}=12.7gHClO_3

Best regards.

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If a star is shown ti be 33.11 trillion killometers away , how many light year would that be
adoni [48]
Use proportions.

1 lightyear = <span>9.4605284 trillion kilometers
</span><span>x light years </span>≈<span> 33.31 </span>trillion kilometers
<span>
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What is the name for the compound li2so4
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Answer:

Explanation:

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Asbestos, silica, and what else are material hazards which can pose severe dangers to construction workers health?
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