Answer:
P-positive
N-negative
E-no charge
Explanation:
The given data is as follows.
(NaCl) = 
(H-O=C-ONO) = 
(HCl) = 
Conductivity of monobasic acid is 
Concentration = 0.01 
Therefore, molar conductivity (
) of monobasic acid is calculated as follows.

= 
= 
= 
Also,
= 
= 
= 
Relation between degree of dissociation and molar conductivity is as follows.

= 
= 0.1254
Whereas relation between acid dissociation constant and degree of dissociation is as follows.
K = 
Putting the values into the above formula we get the following.
K = 
= 
= 
= 
Hence, the acid dissociation constant is
.
Also, relation between
and
is as follows.

= 
= 3.7454
Therefore, value of
is 3.7454.
Answer:
The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.
Explanation:
How does the concept of conservation of mass apply to chemical reactions? the reactants and products have exactly the same atoms. the reactants and products have exactly the same molecules. the change in the amount of matter is equal to the change in energy.
can someone help me with my qustions?
Carbon will have 4 valence electrons. It will have 2 in the p orbital and 2 in the s orbital. You can see this when you find the noble gas configuration of carbon which is [He]2s²2p² showing that carbon has 4 valence electrons.
I hope this helps. Let me know if anything is unclear.