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AnnyKZ [126]
3 years ago
12

In which of the following sets are the charges given correctly for all the

Chemistry
1 answer:
Ronch [10]3 years ago
3 0

Answer:

B) K⁺, Sr²⁺ , O²⁻

Explanation:

Potassium is present in group one. It is alkali metal and have one valance electron.Potassium need to lose its one valance electron and form cation to get complete octet.

That's why it shows K⁺.

Sr is alkaline earth metal. It is present in group two. It has two valance electrons. Strontium needed to lose its two valance electrons and get stable electronic configuration.

When it loses its two valance electrons it shows cation with charge of +2.

Sr²⁺

Oxygen is present in group 16. It has sex valance electrons. It needed two more electrons to complete the octet. That's why oxygen gain two electron and form anion with a charge of -2.

O²⁻

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When 0.50 L of a 12 M solution is diluted to 1.0 L, what is the resulting molarity?
Lyrx [107]

Answer:

The resulting molarity is 6M.

Explanation:

A dilution consists of the decrease of concentration of a substance in a solution (the higher the volume of the solvent, the lower the concentration).

We use the formula for dilutions:

C1 x V1 = C2 x V2

12 M x 0,5L = C2 x 1,0 L

C2= (12 M x 0,5 L)/1,0 L

<em>C2= 6 M</em>

5 0
3 years ago
The reaction of cr2+(aq) with cr2o2−7(aq) in acid solution to form cr3+(aq). calculate δg∘rxn.
Nat2105 [25]
The reaction is:
6 Cr²⁺ + Cr₂O₇²⁻ + 14 H⁺ → 8 Cr³⁺ + 7 H₂O

E₀ = 1.33 - (-0.5) = 1.83 V

ΔG = - n f E₀
      = - 6 * 96485  * 1.83
      = - 1059405.3 J / mol
      = - 1059.4 kJ / mol
8 0
3 years ago
Read 2 more answers
What compound are formed with lithium and selenium?
love history [14]

Answer:

Lithium selenide Lithium selenide (Li2Se) 12136-60-6 Dilithium selenide lithium selenidolithium

Molecular Weight 92.9 g/mol

Dates Modify 2020-11-15 Create 2005-08-08

5 0
3 years ago
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Giving 30 points!! please help &lt;3
TiliK225 [7]

Answer:

below :)

Explanation:

Bones, droppings, and other dead matter

Energy storage molecules, cellular respiration

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3 0
2 years ago
Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:
posledela

Answer: The value of the equilibrium constant Kc for this reaction is 3.72

Explanation:

Equilibrium concentration of HNO_3 = \frac{15.5g}{63g/mol\times 9.5L}=0.026M

Equilibrium concentration of NO = \frac{16.6g}{30g/mol\times 9.5L}=0.058M

Equilibrium concentration of NO_2 = \frac{22.5g}{46g/mol\times 9.5L}=0.051M

Equilibrium concentration of H_2O = \frac{189.0g}{18g/mol\times 9.5L}=1.10M

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c  

For the given chemical reaction:

2HNO_3(aq)+NO(g)\rightarrow 3NO_2(g)+H_2O(l)

The expression for K_c is written as:

K_c=\frac{[NO_2]^3\times [H_2O]^1}{[HNO_3]^2\times [NO]^1}

K_c=\frac{(0.051)^3\times (1.10)^1}{(0.026)^2\times (0.058)^1}

K_c=3.72

Thus  the value of the equilibrium constant Kc for this reaction is 3.72

5 0
2 years ago
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