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yulyashka [42]
3 years ago
6

The best recrystallization solvent for benzil was ethanol. what would be the consequence of using acetone as the recrystallizati

on solvent for benzil? explain.
Chemistry
1 answer:
Vitek1552 [10]3 years ago
8 0
<span>Recrystallization is another method of purification of solids in which an impure solid is crystallize repeatedly to obtain amore pure solid and a larger one. Ethanol is better suited as solvent in recrystallization of benzene than acetone because it becomes soluble with benzene at a higher temperature. Ethanol is non polar and may react well with benzyl but acetone are is non polar. A difference in their polarity, especially in heating both benzyl and the solvent can lead to more impurities that cannot be removed.</span>
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Is water a solid, liquid, or gas at 245 kelvin
Korvikt [17]
The answer is water is a liquid
3 0
4 years ago
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How do cations of the same charge change in radius as you move down a column in the periodic table?
zepelin [54]

Answer:

<em>The cations of the same charge </em><u>increase </u><em>in radius as you move down a column in the periodic table.</em>

Explanation:

Moving down a column in the periodic table means to increase the main energy level and keeping the number of electrons in the outermost shell (the number of valence electrons).

The metals (elements in the left side of the periodic table) form positive ions, named cations, when they lose one or more valence electrons.

To depict this more clearly, consider, for example, the column 1 in the periodic table, which is the group of alkal metals: Li, Na, K, Rb, Cs, and Fr.

As you move down that column you ge the following results

Element     Period                          Number of                   Main cation

                  (main energy level)     valence electrons

Li                 2                                   1                                    Li⁺

Na               3                                   1                                    Na⁺

K                  4                                   1                                   K⁺

Rb                5                                   1                                   Rb⁺

Cs                6                                   1                                   Cs⁺

Fr                 7                                   1                                    Fr⁺

Then, in the last column of the previous table, you see that all the cations have the same charge, because each one is formed after lossing the same number of electrons from the neutral atom (1).

Since, as you move down the column in the periodic table, the valence electrons are in higher main energy levels, which means that the size of both the neutral atom and the and the resultant cation formed after losing the valence electron are bigger than the cation of the previous level. Hence, as a general rule, the radius of the cations of the same charge increase as you move down a colum in the periodic table.

4 0
3 years ago
A solution has a pH = 4.63. What is the [H3O+] concentration?
LUCKY_DIMON [66]

Explanation:

The pH of a solution can you be found by using the formula

pH = - log [ { H_3O}^{+}]

Since we are finding the [H3O+] , substitute the value of the pH and find it's antilog

We have

4.63 =  -  log[ { H_3O}^{+}] \\ [ { H_3O}^{+}]   =  {10}^{ - 4.63}  \\   \\  = 2.344 \times  {10}^{ - 5} mol {dm}^{ - 3}

Hope this helps you

7 0
3 years ago
You are given a glass which was almost filled with ice water in the lab to observe.
Ira Lisetskai [31]
You would witness h2o in its solid and liquid phases.
4 0
3 years ago
You have 500.0 ml of a buffer solution containing 0.30 m acetic acid (ch3cooh) and 0.20 m sodium acetate (ch3coona). what will t
Nataly [62]
First, we should get moles acetic acid = molarity * volume

                                                                =0.3 M * 0.5 L

                                                                =  0.15 mol

then, we should get moles acetate = molarity * volume

                                                           = 0.2 M * 0.5L

                                                           = 0.1 mol

then, we have to get moles of OH- which added:

moles OH- = molarity  * volume

                   = 1 M    * 0.02L

                  = 0.02 mol

when the reaction equation is:


                 CH3COOH  +  OH-  → CH3COO-   +  H2O


moles acetic acid after adding OH- = (0.15-0.02) 
                                             
                                                            =  0.13M                                       

moles acetate after adding OH- =  (0.1 + 0.02)

                                                      =   0.12 M

Total volume = 0.5 L + 0.02 L= 0.52 L

∴[acetic acid] = moles acetic acid after adding OH- / total volume

                        = 0.13mol / 0.52L

                       = 0.25 M

and [acetate ) = 0.12 mol / 0.52L
 
                        = 0.23 M

by using H-H equation we can get PH:

PH = Pka + ㏒[salt/acid]

when we have Ka = 1.8 x 10^-5

∴Pka = -㏒Ka 

        = -㏒ 1.8 x 10^-5

       = 4.7

So by substitution:

∴ PH = 4.7 + ㏒[acetate/acetic acid]

         = 4.7 + ㏒(0.23/0.25)

        = 4.66
6 0
3 years ago
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