In the chemical equation below, name the reactant(s) and product(s).

Chemistry

1 answer:

Olenka [21]2 years ago

4 0

Answer:Methane(CH4) and dioxygen(O2) are the reactants

Carbon dioxide(CO2) and water(H2O) are the products

Explanation:

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At room temperature (208C) and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less tha

Zina [86]

Total density of filled ball with carbon dioxide gas: $\frac{012g+1.0248g}{0.560L} = 2.044g/L$

The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). The ball filled with carbon dioxide will not float in the air because total density of filled ball is greater than the density of an air. Density of the evacuated ball D = 0.214 g/L

Density of carbon dioxide gas = $d_1 = 1.830g/L$

Mass of the carbon dioxide gas : $1.830g/L \times 0.560L = 1.0248g$

Learn more about Mass and Density here:

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4 0

1 year ago

I have a question on my Chem homework. It's asking "How many molecules of N2O4 are in 76.3 g N2O4? The molar mass of N2O4 is 92.

evablogger [386]

Here, Molar mass of N2O4 = 92.02 g/mol
So, Number of molecules in 1 mole (92.02 g) = 6.023 * 10²³
Number of molecules in 76.3 g = 6.023 * 10²³ / 92.02 * 76.3
= 6.023 * 10²³ / 1.20
= 5 * 10²³

In short, Your Answer would be approx. 5 * 10²³ molecules

Hope this helps!

7 0

3 years ago

El volumen de un gas en un recipiente cerrado es de 3.5 litros a una temperatura de 25oC y una atmósfera constante de presión. ¿

polet [3.4K]

Answer:

El volumen del gas en el recipiente es 3.29 L si se disminuye la temperatura a 7°C

Explanation:

La Ley de Charles es una ley de los gases que relaciona el volumen y la temperatura de una cierta cantidad de gas a presión constante.

Esta ley establece que el volumen es directamente proporcional a la temperatura del gas. Es decir que si la temperatura aumenta, el volumen del gas aumenta, mientras que si la temperatura del gas disminuye, el volumen disminuye.

Matemáticamente, si la cantidad de gas y la presión permanecen constantes, el cociente entre el volumen y la temperatura siempre tiene el mismo valor:

$\frac{V}{T}=k$

Suponiendo un cierto volumen de gas V1 que se encuentra a una temperatura T1 al comienzo del experimento, al variar el volumen de gas hasta un nuevo valor V2, entonces la temperatura cambiará a T2, y se cumplirá:

$\frac{V1}{T1}=\frac{V2}{T2}$