All categories

2 years ago

In the chemical equation below, name the reactant(s) and product(s).

Chemistry

1 answer:

Olenka [21]2 years ago

4 0

Answer:Methane(CH4) and dioxygen(O2) are the reactants

Carbon dioxide(CO2) and water(H2O) are the products

Explanation:

You might be interested in

The true absorbance for a 1.0 x 10 −5 M solution is 0.7526. If the percentage stray light for a spectrophotometer is 0.56%, calc

Korvikt [17]

Answer:

The percentage deviation is $\Delta M = 1.87$ %

Explanation:

From the question we are told that

The concentration is of the solution is $C = 1.0*10^{-5} M$

The true absorbance A = 0.7526

The percentage of transmittance due to stray light $z = 0.56$ % $=\frac{0.56}{100} = 0.0056$

Generally Absorbance is mathematically represented as

$A = -log T$

Where T is the percentage of true transmittance

Substituting value

$0.7526 = - log T$

$T = 10^{-0.7526}$

$= 0.177$

$= 17.7$ %

The Apparent absorbance is mathematically represented

$A_p = -log (T +z)$

Substituting values

$A_p = -log(0.177 + 0.0056)$

$= -log(0.1826)$

= 0.7385

The percentage by which apparent absorbance deviates from known absorbance is mathematically evaluated as

$\Delta A = \frac{A -A_p}{A} * \frac{100}{1}$

$= \frac{0.7526 - 0.7385}{0.7526} * \frac{100}{1}$

$\Delta A = 1.87$ %

Since Absorbance varies directly with concentration the percentage deviation of the apparent concentration from know concentration is

$\Delta M = 1.87$ %

6 0

4 years ago

Someone thought there was water in Beaker C. He drank some and quickly spat out.He said that it was salty. Explain why this happ

fomenos

Answer:

He assumed wrongly

Explanation:

It happened this way because the person assumed wrongly.

Most other compounds have the same physical appearance as water especially when in liquid form.

This can be a very tricky one in the laboratory.
The sense of taste is not the best way to fathom what a particular compound is made up of.
This is the reason why this student or person faced this sort of problem.
Water has different properties that can be tested for using simple techniques in the laboratory.

4 0

3 years ago

Most particles would travel____from their source to a screen that lit up when struck.

quester [9]

Answer: in a straight path!

Explanation: hope this helps

5 0

3 years ago

How many moles are represented by 3.01x10^23 helium atoms

Alex787 [66]

Answer:

b. 0.50 moles

Explanation:

To solve this problem we use Avogadro's number (6.023x10²³ atoms/mol).

By dividing the number of atoms (or molecules) by that number, we can calculate how many moles they represent.

3.01x10²³ atoms ÷ 6.023x10²³ atoms/mol = 0.50 moles

So the answer is option b. 0.50 moles.

4 0

3 years ago

PLEASE HELP I HAVE THIS TEST TOMORROW AM GIVING MORE POINTS THAN I SHOULD

zavuch27 [327]

Answer:

41.11 g of Ca(OH)2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaO + H2O —> Ca(OH)2

Next, we shall determine the masses of CaO and H2O that reacted and the mass of Ca(OH)2 produced from the balanced equation. This can be obtained as follow:

Molar mass of CaO = 40 + 16 = 56 g/mol

Mass of CaO from the balanced equation = 1 × 56 = 56 g

Molar mass of H2O = (2x1) + 16

= 2 + 16

= 18 g/mol

Mass of H2O from the balanced equation = 1 × 18 = 18 g

Molar mass of Ca(OH)2 = 40 + 2(16 + 1)

= 40 + 2(17)

= 40 + 34

= 74 g/mol

Mass of Ca(OH)2 from the balanced equation = 1 × 74 = 74 g

From the balanced equation above,

56 g of CaO reacted with 18 g of H2O to produce 74 g of Ca(OH)2.

Finally, we obtained the mass of calcium hydroxide, Ca(OH)2 produced from the reaction of 33 g of CaO and 10 g of H2O. This can be obtained as follow:

From the question given above, we were told that when 33 g of CaO and 10 g of H2O reacted, 2 g of CaO were remaining. This implies that H2O is the limiting reactant and CaO is the excess reactant.

Thus, we shall use the limiting reactant to determine the mass of calcium hydroxide, Ca(OH)2 produced because it will give the maximum yield as all of it is consumed in the reaction.

The limiting reactant is H2O and the mass of calcium hydroxide, Ca(OH)2 produced can be obtained as follow:

From the balanced equation above,

18 g of H2O reacted to produce 74 g of Ca(OH)2.

Therefore, 10 g of H2O will react to produce = (10 × 74)/18 = 41.11 g of Ca(OH)2.

Therefore, 41.11 g of Ca(OH)2 were obtained from the reaction.

3 0

3 years ago