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Oxana [17]
4 years ago
14

iron combines with oxygen to form rust. given the chemical reaction, how many grams of rust would be produced if 3 grams of reac

tants were consumed
Chemistry
1 answer:
tia_tia [17]4 years ago
8 0

Answer:

I believe its 1 gram

Explanation:

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How does chromium oxide improve the properties of stainless steel?
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It protects the alloy against rusting.

Stainless steels contain more than 10% chromium by mass, but almost no carbon. Stainless steels are durable because chromium forms an oxide that protects the steel from rusting. But stainless steel is more brittle than steels that contain more carbon.
6 0
3 years ago
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1. How do metals and non-metals react with acids? Write and explain the chemical equation for the reaction of magnesium with sul
Nata [24]

Answer:

1. How do metals and non-metals react with acids?

Ans : Non metals does not react with acids while metals react with acids and produce hydrogen gas that burns with a 'pop'sound.

2. Write and explain the chemical equation for the reaction of magnesium with sulphuric acid and aluminium with hydrochloric acid.

Magnesium + sulphuric acid = Hydrogen + salt

Mg(s) + H2SO4 (aq) MgSO 4(aq) +H2 (g)

Aluminium + Hydrochloric acid = Hydrogen + Aluminium chloride

2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g)

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3 years ago
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A compound X is used for disinfecting drinking water supply prepared from slaked lime. (2) a. Identify the compound X b. Write t
Diano4ka-milaya [45]

Answer:

slaked lime - Ca(OH)2

Ca(OH)2 + CO2 ----> CaCO3(solid) + H2O

X is CO2

6 0
3 years ago
A solution is prepared by mixing 0.10 of 0.12 M sodium chloride with 0.23 L of a 0.18 M magnesium chloride solution. What is the
Ad libitum [116K]

Answer:

pCl⁻ = 0.54

Explanation:

First we <u>calculate how many Cl⁻ moles are coming from each substance</u>, using the <em>given volumes and concentrations</em>:

  • 0.12 M NaCl * 0.10 L = 0.012 mol NaCl = 0.012 mol Cl⁻
  • 0.18 M MgCl₂ * 0.23 L = 0.0414 mol MgCl₂ = (0.0414 * 2) 0.0828 mol Cl⁻

The final volume of the mixture is = 0.10 L + 0.23 L = 0.33 L

Now we <u>calculate [Cl⁻]</u>, using the<em> total number of Cl⁻ moles and the final volume:</em>

  • [Cl⁻] = (0.012 mol + 0.0828 mol) / 0.33 L = 0.29 M

Finally we <u>calculate the pCl⁻ of the resulting solution</u>:

  • pCl⁻ = -log[Cl⁻]
  • pCl⁻ = 0.54
7 0
3 years ago
What will be the pH of a buffer solution containing an acid of pKa7.5, with an acid concentration exactly one fourth of that of
I am Lyosha [343]

Answer: pH of buffer solution is 8.1

Explanation:

The formula for the Henderson–Hasselbalch equation is:

pH=pK_a+\log\frac{[A^-]}{[HA]}

pH is the concentration of [H^+]

pK_a is the acid dissociation constant,

A^- and HA are concentrations of the conjugate base and starting acid.

Putting in the values we get:

pH=7.5+\log\frac{x}{\frac{x}{4}}

pH=8.1

Thus pH of buffer solution is 8.1

3 0
3 years ago
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