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3 years ago

Define a named tuple Player that describes an athlete on a sports team. Include the fields name, number, position, and team.

Engineering

1 answer:

Soloha48 [4]3 years ago

7 0

Answer:

Explanation:

we would be analyzing this question with the important code given

#code :

from collections import namedtuple

#creating a named tuple named 'Player' with field names name, number, position and team

Player = namedtuple('Player',['name','number','position', 'team'])

cam = Player('Cam Newton','1','Quarterback','Carolina Panthers')

lebron = Player('Lebron James','23','Small forward','Los Angeles Lakers')

print(cam.name+'(#'+cam.number+')'+' is a '+cam.position+' for the '+cam.team+'.')

print(lebron.name+'(#'+lebron.number+')'+' is a '+lebron.position+' for the '+lebron.team+'.')

NB:

Lebron James (#23) rep. Small forward for the LA lakers

Cam Newton(#1) rep. a Quaterback for the Carolina Panthers

cheers i hope this helps

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Answer:

Product deformulation analysis, also known as “chemical reverse engineering” is the process of analytically breaking down a drug, material, or product’s formulation to separate and determine the specific identity and exact quantity of both its major and minor constituent components. This process can be vital to a wide range of scenarios such as identifying hazardous components in consumer products, determining potential patent infringement, or improving competitive positioning of existing or new product(s).

Explanation:

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3 years ago

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The volume of 1.5 kg of helium in a frictionless piston-cylinder device is initially 6 m3. Now, helium is compressed to 2 m3 whi

coldgirl [10]

Answer:

The initial temperature will be "385.1°K" as well as final will be "128.3°K".

Explanation:

The given values are:

Helium's initial volume, v₁ = 6 m³

Mass, m = 1.5 kg

Final volume, v₂ = 2 m³

Pressure, P = 200 kPa

As we know,

Work, $W=p(v_{2}-v_{1})$

On putting the estimated values, we get

⇒ $=200000(2-6)$

⇒ $=200000\times (-4)$

⇒ $=800,000 \ N.m$

Now,

Gas ideal equation will be:

⇒ $pv_{1}=mRT_{1}$

On putting the values. we get

⇒ $200000\times 6=1.5\times 2077\times T_{1}$

⇒ $T_{1}=\frac{1200000}{3115.5}$

⇒ $=385.1^{\circ}K$ (Initial temperature of helium)

and,

⇒ $pv_{2}=mRT_{2}$

On putting the values, we get

⇒ $200000\times 2=1.5\times 2077\times T_{2}$

⇒ $T_{2}=\frac{400000}{3115.5}$

⇒ $=128.3^{\circ}K$ (Final temperature of helium)

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3 years ago

A 1:50 scale model of a ship is towed at 4.8 km/hr using a force of 9 N. If we assume the same fluid in the model as in the prot

Mashutka [201]

Answer:

A: density and gravity

Explanation:

The Froude Number is defined as a dimensionless parameter that measures the ratio of the force of inertia on an element of fluid to the weight of the fluid element. In simple terms, it's the force of inertia divided by the gravitational force.

Froudes number is usually expressed as;

Fr = v/√(gd)

Where;

Fr = froude number

v = velocity

g = gravitational acceleration = specific weight/density

d = depth of flow

Now, to calculate the corresponding speed and force in the prototype, it means we have to use equal froude number and thus this will mean that it has to be dominated by gravity and density.

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3 years ago

5. A biscuit joint does not require glue.<br> True or False

OLga [1]

Answer:

false

Explanation:

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3 years ago

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Consider the flow field given by V ! =xy2^i− 1 3 y3^j+xyk ^. Determine (a) the number of dimensions of the flow, (b) if it is a

Basile [38]

Answer:

a) The flow has three dimensions (3 coordinates).

b) ∇V = 0 it is a incompressible flow.

c) ap = (16/3) i + (32/3) j + (16/3) k

Explanation:

Given

V = xy² i − (1/3) y³ j + xy k

a) The flow has three dimensions (3 coordinates).

b) ∇V = 0

then

∇V = ∂(xy²)/∂x + ∂(− (1/3) y³)/∂y + ∂(xy)/∂z

⇒ ∇V = y² - y² + 0 = 0 it is a incompressible flow.

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⇒ ap = xy²*(y² i + y k) - (1/3) y³*(2xy i − y² j + x k) + xy*(0)

⇒ ap = (xy⁴ - (2/3) xy⁴) i + (1/3) y⁵ j + (xy³ - (1/3) xy³) k

⇒ ap = (1/3) xy⁴ i + (1/3) y⁵ j + (2/3) xy³ k

At point (1, 2, 3)

⇒ ap = (1/3) (1*2⁴) i + (1/3) (2)⁵ j + (2/3) (1*2³) k

⇒ ap = (16/3) i + (32/3) j + (16/3) k

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4 years ago