Answer:
QH = 227.8 km ≅ 228 km
Step-by-step explanation:
∵ The bearing from H to P is 084°
∵ The bearing from P to Q is 210°
∵ The distance from H to P = 340 km
∵ The distance from P to Q = 160 km
∴ The angle between 340 and 160 = 360 - 210 - (180 - 84) = 54°
( 180 - 84) ⇒ interior supplementary
By using cos Rule:
(QH)² = (PH)² + (PQ)² - 2(PH)(PQ)cos∠HPQ
(QH)² = 340² + 160² - 2(340)(160)cos(54) = 51904.965
∴ QH = 227.8 km ≅ 228 km
The answer is 127.16 pi m³, hope this helps.
Answer:
20 cm
Step-by-step explanation:
Shadow of vertical poles : 6m ; 15m
Length of poles : 8cm ; h
8cm long pole = shadow length, 6m
h cm long pole = shadow length, 15 m
Using cross multiplication :
8cm * 15 m = h cm * 6m
120 = 6h
h = 120 / 6
h = 20 cm
Height of second pole = 20cm
Its $800 because to find interest u can use the formula I=PRT p is principal which is 500 times r which is rate-15/100(=15%) times 4
so the interest is 500×15/100×4=300
then u add 300 to 500 because the interest adds more money to the loan
Answer:
The surface area for this cylinder is 252*pi square inches.
Step-by-step explanation:
The surface area of a cylinder can be calculated by using the following formula:
surface area = 2*pi*r² + 2*pi*r*h
Applying the data from the problem, we have:
surface area = 2*pi*(6)² + 2*pi*(6)*15
surface area = 2*pi*36 + 180*pi
surface area = 72*pi + 180*pi
surface area = 252*pi
The surface area for this cylinder is 252*pi square inches.
