The reaction between the magnesium, Mg, and the hydrochloric acid, HCl is given in the equation below,
Mg + 2HCl --> H2 + MgCl2
The number of moles of HCl that is needed for the reaction is calculated below. n = (0.4681 g Mg)(1 mol Mg/24.305 g Mg)(2 mol HCl/1 mol Mg) n = 0.0385 mols HCl
From the given concentration, we calculate for the required volume. V = 0.0385 mols HCl/(0.650 mols/L) V = 0.05926 L or 59.26 mL
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