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Sonja [21]
2 years ago
9

In solid I₂, is the distance between the two I nuclei of one I₂ molecule longer or shorter than the distance between two I nucle

i of adjacent I₂ molecules? Explain.
Chemistry
1 answer:
Crazy boy [7]2 years ago
4 0

Shorter because the I-I bond in the I2 molecule is covalent whereas the bond between adjacent molecules is due to dispersion.

<h3>What is bond length?</h3>

Bond length typically falls between 0.1 and 0.2 nm. Covalent radius is the term used to describe the length of a connection formed between two comparable atoms. The order of the bond or the quantity of linked electrons between two atoms determines the bond length.

<h3>What connection exists between the length and the strength of a bond?</h3>

The C-C bond in alkanes must be the longest since it is the weakest, and the C-C bond in alkynes must be the shortest because it appears to be the strongest, according to the data. We determined in the preceding section that the bond strength is inversely correlated to the bond length.

<h3>How can bond length be calculated in chemistry?</h3>
  • The bond gets shorter as the atoms get smaller.
  • The length of the bond decreases as bond multiplicity increases.
  • The shorter the bond, the higher the effective nuclear charges of the bound atoms.

Learn more about bond length:

brainly.com/question/13054857

#SPJ4

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Which of the following solutions would show the greatest conductivity at 30°C?
Nataly_w [17]
Your answer will be A
7 0
3 years ago
A volume of 125 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If
VMariaS [17]

Answer:

41.9 g

Explanation:

We can calculate the heat released by the water and the heat absorbed by the steel rod using the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity

m: mass

ΔT: change in temperature

If we consider the density of water is 1.00 g/mol, the mass of water is 125 g.

According to the law of conservation of energy, the sum of the heat released by the water (Qw) and the heat absorbed by the steel (Qs) is zero.

Qw + Qs = 0

Qw = -Qs

cw × mw × ΔTw = -cs × ms × ΔTs

(4.18 J/g.°C) × 125 g × (21.30°C-22.00°C) = -(0.452J/g.°C) × ms × (21.30°C-2.00°C)

ms = 41.9 g

3 0
3 years ago
Which best describes a chain reaction associated with a nuclear reaction? Neutrons released during a fusion reaction cause other
atroni [7]
The statement that describes a chain reaction brought about by a nuclear reaction is "neutrons <span>released during a fission reaction cause other nuclei to split." This is applicable to fission reactions only wherein atoms split and produce neutrons that also cause further atoms to split, thus creating a chain or series of reactions.</span>
8 0
4 years ago
Read 2 more answers
William measures a test tube and finds that the mass of the test tube is 5g. He places the lone reactant in the test tube and fi
iogann1982 [59]

86 percent is the percent yield for this experiment if he expected to produce 5g of product.

Explanation:

Given that:

mass of test tube = 5 grams

mass of test tube + reactant is 12.5 grams

mass of reactant = ( mass of test tube + reactant ) - (mass of test tube)

mass of reactant = 12.5 -5

                             = 7.5 grams

when 7.5 grams of reactant is heated mass of test tube was found to be 9.3 grams.

so mass of product formed = 9.3 - 5

                                             = 4. 3 grams of product is formed (actual yield)

However, he expected the product to be 5 grams (theoretical yield)

Percent yield = \frac{actual yield}{theoretical yield} x 100

          putting the values in the formula:

percent yield = \frac{4.3}{5} x 100

                     = 86 %

86 percent is the percent yield.

5 0
3 years ago
The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 m
monitta

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

                                              = 130 x 10^{-12} m

The diameter of a vanadium atom = 2 x radius

                                                         = 2 x 130 x 10^{-12}

                                               = 260 x 10^{-12} m

Given a distance of 1.30 mm = 1.30 x 10^{-3} m,

The number of vanadium atoms required to span the distance = \frac{1.3*10^{-3} }{260*10^{-12} }

                                                  = 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

3 0
3 years ago
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