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3 years ago

8

When using the right-hand rule to determine the direction of the magnetic field around a current-carrying wire, which part of th

e right hand points in the direction of the magnetic field?
palm

fingers

back

thumb

2 answers:

kirza4 [7]3 years ago

8 0

Answer:

Curled fingers will give the direction of magnetic field.

Explanation:

The right hand thumb rule states that hold any current carrying conductor in your right hand such that the thumb is pointing in the direction of electric current. Then the curled finger will give the direction of magnetic field.

For example : when the current in the wire is flowing towards right, then the curled finger will give the direction of magnetic field i.e. the field is towards bottom.

Hence, the correct option is (c) fingers.

Margarita [4]3 years ago

5 0

Your answer will be fingers

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<h3>Question:</h3>

How to find g (acceleration due to gravity)

<h3>Solution:</h3>

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3 years ago

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jeka57 [31]

Answer:

Here is the complete question:

https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632

a) Current for long straight wire $=3.7\ MA$

b) Current at the center of the circular coil $=2.48\times 10^{5}\ A$

c) Current near the center of a solenoid $236.8\ A$

Explanation:

⇒ Magnetic Field due to long straight wire is given by (B),where $B=\frac{\mu\times I}{2\pi(r) },so\ I=\frac{B\ 2\pi(r)}{\mu}$

$\mu=4\pi \times 10^{-7}\ \frac{henry}{m}$

Plugging the values,

Conversion $1\times 10^6 A = 1\ MA$ ,and $2cm=\frac{2}{100}=0.02\ m$

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⇒Magnetic Field at the center due to circular coil (at center) is given by, $B=\frac{\mu\times I (N)}{2(a)}$

So $I= \frac{2B(a)}{\mu\ N} = \frac{2\times 37.2\times 0.42}{4\pi\times 10^{-7}\times 100}=2.48\time 10{^5}\ A$

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3 years ago