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4 years ago

When two or more forces act together on an object what do they combine to form

1 answer:

7 0

Without knowing anything about their magnitudes or directions, the only thing you can always say about thier combination is that it's the "net force" on the object.

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Why sheets of newspaper can be used to keep ice cream cold and keep fish and chips hot?

stich3 [128]

Answer: Paper

Explanation: It is a insulator

7 0

4 years ago

An elevator lifts a total mass of 1.1×103 kg a distance of 40.0 m in 12.5 s. How much power does the elevator deliver?

Harman [31]

The power delivered by the elevator is 34496 W.

<h3>What is power?</h3>

Power is the rate at which energy is used up.

To calculate the power delivered by the elevator, we use the formula below.

Formula:

P = mgh/t.............. Equation 1

Where:

P = Power delivered by the elevator
m = Total mass on the elevator
g = acceleration due to gravity
h = Height

From the question,

Given:

m = 1.1×10³ kg
h = 40 m
t = 12.5 s
g = 9.8 m/s²

Substitute these values into equation 1

P = 1.1×10³×40×9.8/12.5
P = 34496 W.

Hence, the power delivered by the elevator is 34496 W.

Learn more about power here: brainly.com/question/24858512

#SPJ1

8 0

2 years ago

What is the mass of a liquid having a density of 1.50 g/ml and a volume of 3.5 liters?

PIT_PIT [208]

We know the formula for density = Mass/ volume

So Mass, M = Volume * Density

Volume = 3.5 L= 0.0035 $m^3$

Density = 1.50 g/ml = 1500 $kg/m^3$

Mass, M = 0.0035*1500 = 5.25 kg

So mass of liquid having density 1.50 g/ml and volume 3.5 liters is 5.25 kg.

6 0

4 years ago

Give v=120m/s north and t = 10.2, calculate the displacement

Sedbober [7]

Answer:

Displacement from the starting position is 1224m

Explanation:

The object is moving at 120 meters per second, it does this for 10.2 seconds. Use multiplication to find the answer.

$120 \times 10.2 = 1224$

4 0

3 years ago

Two balls have the same mass of 5.00 kg. Suppose that these two balls are attached to a rigid massless rod of length 2L, where L

olga_2 [115]

Answer:

Explanation:

Given

mass of balls $m= 5 kg$

$N=45.6 rev/s$

angular velocity $\omega =2\pi N=286.55 rad/s$

Length of Rod $2L=1.1 m$

Tension in the Second half of rod

$T_2=m\omega ^2(2L)=2m\omega ^2L$

$T_2=5\times (286.55)^2\times 1.1$

$T_2=451.609 kN$

For First Part

$T_1-T_2=m\omega ^2L$

$T_1=T_2+m\omega ^2L$

$T_1=3 m\omega ^2L$

$T_1=3\times 5\times (286.55)^2\times 0.55$

$T_1=677.41 kN$

7 0

3 years ago