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frozen [14]
3 years ago
5

Draw the following patterns as they would appear when viewed through a compound microscope.:

Physics
2 answers:
grandymaker [24]3 years ago
7 0
A I got right rkmfkvmtmtggffffffff
goblinko [34]3 years ago
3 0
2 j x b
H c e c hope this helppppsssssssss
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What affects fuel consumption in automobiles?
maksim [4K]

Answer:

A and C

Explanation:

drag (the area of lower air pressure behind the car when moving) and mostly air resistance (the work to push the air in front of us away to move through - the faster we go, the stronger the air resists to move aside).

4 0
2 years ago
An electron is released from rest at a distance of 0.300 m from a large insulating sheet of charge that has uniform surface char
jarptica [38.1K]
Yes that is the correct answer
8 0
3 years ago
A cat is chasing a mouse across a 1.3 m tall dining table. The mouse darts to the side and the cat accidentally slides off, land
erastovalidia [21]

Answer:

1) 0.51 seconds.

2) 1.45 m/s.

Explanation:

given, height from which cat falls = 1.3 m

we know that, s = ut + \frac{1}{2}at².

here if we consider cat moment only in downward direction,

intial velocity of cat in downward direction , u = 0.

so, time, t = \sqrt{\frac{2h}{g} }.

⇒ t = \sqrt{\frac{2(1.3)}{9.81} } = 0.51 seconds.

t = 0.51 seconds.

now, consider cat moment only in forward direction

s = ut , since acceleration is zero in forward direction

⇒ u = \frac{s}{t}.

so, u = \frac{0.75}{0.51} = 1.45 m/s .

6 0
3 years ago
Which element has an atomic number of 9 and an atomic mass of 19?
yan [13]

Answer:

fluorine

Explanation:

3 0
3 years ago
Read 2 more answers
The glass in a window is 35 inches wide and 20 inches tall, and standard atmospheric pressure is 14.7 pounds per square inch. Wh
iogann1982 [59]

Answer:103 pounds

Explanation:

Given

width of window b=35 in.

height of window h=20 in.

standard atmospheric pressure P_{outside}=14.7 psi

Also P_{inside}=1.01P_{outside}

Thus Net Force on the window will be the algebraic sum of Force due to outside and inside Pressure .

F_{net}=(P_{inside}-P_{outside})\cdot A

F_{net}=P_{outside}(1.01-1)\times 35\times 20

F_{net}=14.7\times 0.01\times 35\times 20

F_{net}=102.9\ pounds\approx 103\ pounds            

8 0
3 years ago
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