The libero is the player who wears a different color jersey.<br> True or false

a sample of ideal gas is originally at 40 degrees celsius. what is the final temperature of the gas if the volume is doubled and

Assoli18 [71]

Answer:

313 K or 40 degree celsius.

Explanation:

Initial , $V_{i}=V_{0}$

$P_{i}=P_{0}$

$T_{i} =40+273=313K$

Now, final

$P_{f} =\frac{1}{2}P_{0}$

$V_{f} =2V_{0}$

Combined the ideal gas law

$\frac{P_{i}V_{i}}{T_{i}}=\frac{P_{f}V_{f}}{T_{f}} \\\frac{P_{0}V_{0}}{T_{0}}=\frac{1}{2} \frac{P_{0}2V_{0}}{T_{f}} \\T_{f}=T_{0}\\T_{f}=313K$

Therefore, the final temperature of ideal gas is 313 K.

4 0

4 years ago

A 7.0kg skydiver is descending with a constant velocity

Vikentia [17]

Answer:

The air resistance on the skydiver is 68.6 N

Explanation:

When the skydiver is falling down, there are two forces acting on him:

- The force of gravity, of magnitude $mg$ , in the downward direction (where m is the mass of the skydiver and g is the acceleration due to gravity)

- The air resistance, $R$ , in the upward direction

So the net force on the skydiver is:

$F=mg-R$

where

m = 7.0 kg is the mass

$g=9.8 m/s^2$

According to Newton's second law of motion, the net force on a body is equal to the product between its mass and its acceleration (a):

$F=ma$

In this problem, however, the skydiver is moving with constant velocity, so his acceleration is zero:

$a=0$

Therefore the net force is zero:

$F=0$

And so, we have:

$mg-R=0$

And so we can find the magnitude of the air resistance, which is equal to the force of gravity:

$R=mg=(7.0)(9.8)=68.6 N$

6 0

4 years ago

What is the mass of a vehicle that has 50,000 N and 25M/S/S

natali 33 [55]

Answer:

F = 1250000 N

Explanation:

If you have 50,000 S, by 25 M. It would be calculated to 1,250,000 N.

7 0

3 years ago

An object with mass m = 0.56 kg is attached to a string of length r = 0.72 m and is rotating with an angular velocity ω = 1.155

Marta_Voda [28]

Answer:

The centripetal force is 0.54 N.

Explanation:

mass, m = 0.56 kg

radius, r = 0.72 m

angular speed, w = 1.155 rad/s

The centripetal force is given by

$F = m r w^2\\\\F =0.56\times 0.72\times 1.155\times 1.155\\\\F = 0.54 N$

6 0

3 years ago

A 2300-kg car slows down at a rate of 3.0 m/s2 when approaching a stop sign. What is the magnitude of the net force causing it t

weeeeeb [17]

The magnitude of the net force causing the 2300kg car to slow down is 6900N

HOW TO CALCULATE FORCE:

The net force applied on a moving object can be calculated by multiplying the mass of the object by its acceleration. That is;

Force (N) = mass (kg) × acceleration (m/s²)

According to this question, a 2300-kg car slows down at a rate of 3.0 m/s2 when approaching a stop sign. The net force causing the car to stop can be calculated as follows:

F = 2300kg × 3m/s²

F = 6900N

Therefore, the magnitude of the net force causing the 2300kg car to slow down is 6900N.

Learn more at: brainly.com/question/18109210?referrer=searchResults

4 0

3 years ago

The libero is the player who wears a different color jersey. True or false