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3 years ago

(Don't answer that there is no image, its a simple question)

Physics

1 answer:

Aleksandr-060686 [28]3 years ago

3 0

Answer:

yes

Explanation:

of course indeed correct

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I know the acceleration due to gravity (ie 9.8 m/s2) will have a negative sign when falling down, a positive one when going up.

rewona [7]

Answer:

Yes

Explanation:

Accerelation is measured by change in velocity. So naturally, if an object is slowing down, its velocity is decreasing so acceleration is negative. If it is speeding up velocity is increasing so positive acceleration.

(Velocity final - Velocity initial)/t

Note that this does not apply only to gravity, but to all linear accelerations

6 0

2 years ago

Find the westward component of a resultant vector 85.42 unit, 23 degrees W of N

Sindrei [870]

Since the angle is West of North, therefore to find for the westward component (horizontal component) of the vector, we use the sin function:

sin θ = opposite side / hypotenuse = westward component / resultant vector

So the westward component (x) is:

x = 85.42 sin 23

5 0

3 years ago

what kind of wave would be observed in outer space between planets where there is very little matter?

ddd [48]

Shock waves can be observed in outer space between planets where there is very little matter. Although little, plasma does exist in outer space which allows the waves to travel.

5 0

3 years ago

Calculate the change internal energy (Î´e) for a system that is giving off 45.0 kj of heat and is performing 855 j of work on th

adelina 88 [10]

The change in internal energy of a system is given by (second law of thermodynamics)
$\Delta U = Q + W$
where Q is the heat absorbed by the system and W is the work done on the system.

In order to correctly evaluate the internal energy change, we must be careful with the signs of Q and W:
Q positive -> Q absorbed by the system
Q negative -> Q released by the system
W positive -> W done on the system by the surroundings
W negative -> W done by the system on the surroundings

In our problem, the heat released by the system is $Q=-45 kJ=-45000 J$ (with negative sign since it is released by the system), and the work done is $W=-855 J$ still with negative sign because it is performed by the system on the surrounding, so the change in internal energy is
$\Delta U = Q +W=-45000 J - 855 J=-45855 J$

3 0

3 years ago

A fleeing student covered a distance of 210 meters in 35 seconds. what is the student's speed in meters/second? what is the stud

snow_lady [41]

Explanation:

Given that,

A student covered a distance of 210 meters in 35 seconds.

We need to find the student's speed in meters/second and also in meters/minute.

Speed, v = distance (d)/time (t)

So,

$v=\dfrac{210\ m}{35\ s}\\\\=6\ m/s$

We know that, 1 minute = 60 seconds

$6\dfrac{m}{s}=6\times \dfrac{m}{(\dfrac{1}{60})\ \text{minutes}}\\\\=360\ \text{meters/minutes}$

Hence, the student's speed is 6 m/s or 360 meters/minute.

6 0

3 years ago