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photoshop1234 [79]

3 years ago

5

46,054,202 round the underlined number the 5 isunderlined

1 answer:

Scrat [10]3 years ago

8 0

<em>if 5 is to be rounded off, then the rule is, if the next significant digit is equal or greater than 5 it adds up, other wise not..</em>
<em>In this case the next significant digit is 0 which is less than 5 so it will not be added up.</em>

<em>46,054,202 ≈ 46,000,000 Answer</em>

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Answer:

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Step-by-step explanation:

Area =4/3×4/3= 16/9

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ANSWER FAST ITS URGENT

Vlad1618 [11]

Answer:

9) 6.3 units

11) n=6√2 and m=12,

10) m=6√3, n=6

12) 330.6 ft

Step-by-step explanation:

1) The Pythagoras Theorem says that, the square of the hypotenuse is the sum of the squares of the two shorter legs.

Let the missing side, which is the hypotenuse be x.

Then

${x}^{2} = {2}^{2} + {6}^{2}$

${x}^{2} = 4 + 36$

${x}^{2} = 40$

$x = \sqrt{40}$

$x = 6.3$

The missing side is 6.3 units to the nearest tenth.

2) This is an isosceles right triangle.

This implies that, the two legs are equal.

$n = 6 \sqrt{2}$

The hypotenuse can be found using Pythagoras Theorem.

${m}^{2} = {(6 \sqrt{2} )}^{2} + {(6 \sqrt{2} )}^{2}$

${m}^{2} = 36(4)$

$m = \sqrt{36 \times 4} = 6 \times 2 = 12$

3) The side lengths of 30°-60°-90° are in the ratio, 2x,x√3,x

From the diagram, the hypotenuse is 12, therefore the other two legs are

$n = \frac{1}{2} (12) = 6$

and

$m = 6 \sqrt{3}$

4) The height of the monument is 115 feet, the hypotenuse is 350.

By Pythagoras Theorem,

${x}^{2} + {115}^{2} = {350}^{2}$

${x}^{2} = {350}^{2} - {115}^{2}$

${x}^{2} = 109275$

$x = \sqrt{109275} = 330.6 ft$

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3 years ago

PLS HELP ITS MY FINAL EXAM What is the area of the base of the cone below? A cone with height 12 feet and volume 90 feet cubed.

hoa [83]

Answer:

$A=22.5\ \text{feet}^2$

Step-by-step explanation:

We have,

Height of a cone is 12 feet

Volume of the cone is 90 feet

It is required to find the area of the base of the cone.

The base of a cone is circular in shape.

The formula used to find the volume of a cone is given by :

$V=\dfrac{1}{3}\pi r^2 h$

here, $\pi r^2=A$ (area of base of cone)

$V=\dfrac{1}{3}\times Ah\\\\A=\dfrac{3V}{h}\\\\A=\dfrac{3\times 90}{12}\\\\A=22.5\ \text{feet}^2$

So, the area of the base of the cone is $22.5\ \text{feet}^2$ .

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