How many double bonds are in lewis structure of oxygen difluoride, OF2? 1,0, 2, or 3
1 answer:
Answer:
0
Explanation:
An image of the lewis structure of the compound OF2 is shown in the image attached.
A Lewis structure is a structure in which electron pairs on atoms are shown as dots. Sometimes shared electron pairs are shown by a horizontal straight line connecting the two atoms involved.
OF2 has no double bonds as shown in its structure. It is a compound containing only two O-F sigma bonds and no pi-bonds.
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Answer:
Its final temperature is 25.8 °C
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation (ΔT=Tfinal-Tinitial)
When a body transmits heat there is another that receives it. This is the principle of the calorimeter. Then the heat released by the compound will be equal to the heat obtained by the calorimeter.
In this case, you know:
- Q= 14 kJ= 14,000 J
- c= 3.55
- m=1.20 kg= 1200 g (1 kg=1000 g)
- Tfinal= ?
- Tinitial= 22.5 °C
Replacing:
Solving:
3.3=Tfinal - 22.5 C
3.3 + 22.5=Tfinal
Tfinal= 25.8 °C
<u><em>Its final temperature is 25.8 °C</em></u>