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4 years ago

How many double bonds are in lewis structure of oxygen difluoride, OF2? 1,0, 2, or 3

Chemistry

1 answer:

solmaris [256]4 years ago

5 0

Answer:

Explanation:

An image of the lewis structure of the compound OF2 is shown in the image attached.

A Lewis structure is a structure in which electron pairs on atoms are shown as dots. Sometimes shared electron pairs are shown by a horizontal straight line connecting the two atoms involved.

OF2 has no double bonds as shown in its structure. It is a compound containing only two O-F sigma bonds and no pi-bonds.

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The field of corn shown below was grown with 250 L/ha herbicide and no insecticide. Based what do you observe work what’s the re

Len [333]

Based on the fact that only herbicide was used to grow the corn, this means that the resistance type of the corn are caterpillars.

<h3>What are herbicide and insecticide?</h3>

Herbicide are chemicals used to control and kill weeds that could hinder crop production while insecticides are chemicals used to control insect pests.

According to this question, a field of corn was grown with 250 L/ha herbicide and no insecticide. This means that only herbs or weeds are being controlled on the field.

Therefore, it can be said that the corn plants are the type that are resistant to caterpillars, which are examples of insects.

Learn more about herbicide at: brainly.com/question/9166713

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2 years ago

Which type of reaction will occur when equal volumes of 0.1 M HCl and 0.1 M NaOH are mixed

Korvikt [17]

The addition of 0.1M HCl and 0.1M NaOH both of equal amounts is considered to be a neutralization reaction. A neutralization reaction is basically a double replacement reaction participated by both an acid and a base. In this case, the NaOH is the base while the HCl is the acid. The reaction will yield the following products: Water (H20) and aqueous Sodium Chloride (NaCl). Neutralization reactions always yield a salt and water as the end products.

4 0

3 years ago

A gas mixture contains SO 2 SO2 ( molar mass = 64 g/mol ) (molar mass=64 g/mol) and no other source of sulfur. If the mixture is

Slav-nsk [51]

Answer : The percentage (by mass) of $SO_2$ in the mixture is 20 %

Explanation :

As we are given that, 10 % sulfur by mass that means 10 grams of sulfur present in 100 grams of mixture.

Mass of sulfur = 10 g

Mass of mixture = 100 g

Now we have to calculate the mass of $SO_2$ .

As, 32 grams of sulfur present in 64 grams of $SO_2$

So, 10 grams of sulfur present in $\frac{10}{32}\times 64=20$ grams of $SO_2$

Thus, the mass of $SO_2$ is 20 grams.

Now we have to calculate the percentage (by mass) of $SO_2$ in the mixture.

$\% \text{ of }SO_2=\frac{\text{Mass of }SO_2}{\text{Mass of mixture}}\times 100$

$\% \text{ of }SO_2=\frac{20g}{100g}\times 100=20\%$

Therefore, the percentage (by mass) of $SO_2$ in the mixture is 20 %

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3 years ago

In a certain crystalline material the vacancy concentration at 25 c is one-fourth that at 80

Luba_88 [7]

At 93 °C, the vacancy concentration will be three times that at 80°C.

The formula for the vacancy concentration in a crystal is a form of the Arrhenius equation.

In logarithmic form, the equation is

ln(N_2/N_1) = (-Q/R)(1/T_2-1/T_1)

where

• Q = the energy required for vacancy formation

• N_2 = the vacancy concentration at T_2

• N_1 = the vacancy concentration at T_1

• R = the gas constant [8.314 J·K^(-1)mol^(-1)]

Let N_80 represent the vacancy concentration at 80 °C.

At 25 °C, ln(N_25/N_80) = ln(0.25N_80/N_80) = ln0.25 = -1.386

∴ -1.386 =(-Q/R)(1/298.15 – 1/353.15) = -1.306 × 10^(-4) × (Q/R)

Q/R = (-1.386)/[-1.306 × 10^(-4)] = 10 620

At T_2, ln(N_T2/N_80) = ln[(3N_80)/N_80] = ln3 = 1.099

∴ 1.099 = -10 620(1/T_2 – 1/353.15) = -10 620/T_2 + 10 620/353.15

= -10 620/T_2 + 30.072

10 620/T_2 = 30.072 – 1.099 = 28.97

T_2 = 10 620/28.97 = 366.4 K = 93 °C

3 0

3 years ago

f 37.4 grams of water decompose at 297 Kelvin and 1.30 atmospheres, how many liters of oxygen gas can be produced?

Allisa [31]

2H2O=2H2+O2
37.4g H2O(1 mol/18.02)=2.07547 mol H2O
PV=nRT
(1.30)(V)=(2.07547)(.0821)(297)
Vwater=38.92898L
38.92898L (1 mol O2/2 mol H2O)=19.46449L O2 gas

4 0

4 years ago

How many double bonds are in lewis structure of oxygen difluoride, OF2? 1,0, 2, or 3​

How many double bonds are in lewis structure of oxygen difluoride, OF2? 1,0, 2, or 3