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bija089 [108]
3 years ago
7

The melting point of copper is 1084°C. How does the energy of the particles in a certain amount of liquid copper compare to the

Energy of the molecules in the same amount of liquid water? Why?
Chemistry
2 answers:
Kobotan [32]3 years ago
8 0

Explanation:

As it is given that melting point of copper is 1084^{o}C. So, it means liquid state of copper will exist at a temperature greater than 1084^{o}C.

Whereas, it is known that liquid state of water exists at above zero degree celsius.

And, kinetic energy of the particles of a substance is directly related to the temperature as follows.

                    K.E = \frac{3}{2} kT

Hence, more is the temperature of a substance more will be the kinetic energy of its molecules.

Therefore, temperature of liquid copper is more than the temperature of liquid water.

Thus, we can conclude that the energy of the particles in a certain amount of liquid copper is greater than the energy of the molecules in the same amount of liquid water.

Fed [463]3 years ago
5 0
Solids' particles move a lot faster and closer together. Liquids' are more spread apart and move slower. So there is more energy in the solid
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Answer:

30 mL VOLUME OF 3.0 M HCl SHOULD BE USED BY THE STUDENT TO MAKE A 1.80 M IN 50 mL OF HCl.

Explanation:

M1 = 3.00 M

M2 = 1.80 M

V2 = 50 .0 mL = 50 /1000 L = 0.05 L

V1 = unknown

In solving this question, we know that number of moles of a solution is equal to the molar concentration multiplied by the volume. To compare two samples, we equate both number of moles and substitute for the required component.

So we use the equation:

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V1 = M2 V2 / M1

V2 = 1.80 * 0.05 / 3.0

V2 = 0.09 /3.0

V2 = 0.03 L or 30 mL

To prepare the sample of 1.80 M HCl in 50.0 mL from a 3.0 M HCl, 30 mL volume should be used.

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