The melting point of copper is 1084°C. How does the energy of the particles in a certain amount of liquid copper compare to the
2 answers:
Explanation:
As it is given that melting point of copper is . So, it means liquid state of copper will exist at a temperature greater than
.
Whereas, it is known that liquid state of water exists at above zero degree celsius.
And, kinetic energy of the particles of a substance is directly related to the temperature as follows.
K.E =
Hence, more is the temperature of a substance more will be the kinetic energy of its molecules.
Therefore, temperature of liquid copper is more than the temperature of liquid water.
Thus, we can conclude that the energy of the particles in a certain amount of liquid copper is greater than the energy of the molecules in the same amount of liquid water.
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Answer:
[H₃O⁺] = 1.4 × 10⁻⁹ M.
Explanation:
NH₄Cl is a salt that dissolves well in water. The 2.5 M NH₄Cl will give an initial NH₄⁺ concentration of 2.5 M.
NH₃ is a weak base. It combines with water to produce NH₄⁺ and OH⁻. The opposite process can also take place. NH₄⁺ combines with OH⁻ to produce NH₃ and H₂O. The final H₃O⁺ concentration can be found from the OH⁻ concentration. What will be the final OH⁻ concentration?
Let the increase in OH⁻ concentration be x. The initial OH⁻ concentration at room temperature is 10⁻⁷ M.
Construct a RICE table for the equilibrium between NH₃ and NH₄⁺:
.
The value for ammonia is small. The value of x will be so small that at equilibrium,
and
.
.
.
.
Again, at room temperature.
Answer:
The addition of sulfate ions shifts equilibrium to the left.
Explanation:
Hello!
In this case, according to the following ionization of strontium sulfate:
It is evidenced that when sodium sulfate is added, sulfate, is actually added in to the solution, which causes the equilibrium to shift leftwards according to the Le Ch athelier's principle. Thus, the answer in this case would be:
The addition of sulfate ions shifts equilibrium to the left.
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