Calculate the eccentricity of an ellipse. The distance between the foci is 5.2 and the length of the major axis is 20.6.Round of
1 answer:
Answer:
The eccentricity of the ellipse is 0.252.
Explanation:
The eccentricity of an ellipse (), dimensionless, can be determined by means of the following expression:
(1)
Where:
- Distance between the foci, dimensionless.
- Length of the major axis, dimensionless.
If we know that and
, then the eccentricity of the ellipse is:
The eccentricity of the ellipse is 0.252.
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Answer:
Q = 143,921 J = 143.9 kJ.
Explanation:
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In this case, according to the given information, it turns out possible for us to calculate the absorbed heat by considering this is a process involving sensible heat associated to the vaporization of water, which is isothermic and isobaric; and thus, the heat of vaporization of water, with a value of about 2259.36 J/g, is used as shown below:
Thus, we plug in the mass and the aforementioned heat of vaporization of water to obtain the following:
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Answer:
"0.60 g" is the appropriate solution.
Explanation:
The given values are:
Volume of base,
= 30 ml
Molarity of base,
= 0.05 m
Molar mass of acid,
= 400 g/mol
As we know,
⇒
On substituting the values, we get
⇒
⇒
⇒
hence,
⇒
On substituting the values, we get
⇒
⇒
⇒