Calculate the eccentricity of an ellipse. The distance between the foci is 5.2 and the length of the major axis is 20.6.Round of
1 answer:
Answer:
The eccentricity of the ellipse is 0.252.
Explanation:
The eccentricity of an ellipse (), dimensionless, can be determined by means of the following expression:
(1)
Where:
- Distance between the foci, dimensionless.
- Length of the major axis, dimensionless.
If we know that and
, then the eccentricity of the ellipse is:
The eccentricity of the ellipse is 0.252.
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Answer:
28.7664 kJ /mol
Explanation:
The expression for Clausius-Clapeyron Equation is shown below as:
Where,
P is the vapor pressure
ΔHvap is the Enthalpy of Vaporization
R is the gas constant (8.314×10⁻³ kJ /mol K)
c is the constant.
The graph of ln P and 1/T gives a slope of - ΔHvap/ R and intercept of c.
Given :
Slope = -3.46×10³ K
So,
- ΔHvap/ R = -3.46×10³ K
<u>ΔHvap = 3.46×10³ K × 8.314×10⁻³ kJ /mol K = 28.7664 kJ /mol</u>
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Answer:
1 : any of more than 100 substances that cannot by ordinary chemical means be separated into different substances Gold and carbon are elements. 2 : one of the parts of which something is made up There is an element of risk in surfing. 3 : the simplest principles of a subject of study the elements of arithmetic.
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