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3 years ago

(factor out) 3x(to the power of 2) -39x+36

1 answer:

7 0

3x² - 39x + 36
3(x²) - 3(13x) + 3(12)
3(x² - 13x + 12)
3(x² - 12x - x + 12)
3(x(x) - x(12) - 1(x) + 1(12))
3(x(x - 12) - 1(x - 12))
3(x - 1)(x - 12)

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The sum of a number and its square is 182. Find the number.

Mars2501 [29]

Answer:

13 and -14 satisfy this condition

Step-by-step explanation:

Let's represent that number as x

and the square of x is x^2

So,

x + x^2 = 182

Subtract 182 from both sides

x + x^2 - 182 = 182 - 182

x + x^2 - 182 = 0

rearrange the quadratic equation

x^2 + x -182 = 0

let's use the quadratic formula

$\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $\frac{-b-\sqrt{b^2-4ac} }{2a}$

a = 1, b = 1, c = -182

$\frac{-1+\sqrt{1^2-4*1*(-182)} }{2*1}$ or $\frac{-1-\sqrt{1^2-4*1*(-182)} }{2*1}$

$\frac{-1+\sqrt{1+728} }{2}$ or $\frac{-1-\sqrt{1+728} }{2}$

$\frac{-1+\sqrt{729} }{2}$ or $\frac{-1-\sqrt{729} }{2}$

$\frac{-1+{27} }{2}$ or $\frac{-1-{27} }{2}$

$\frac{26}{2}$ or $\frac{-28}{2}$

13 or - 14

Lets check

13 + 13^2 = 13 + 169

= 182

Also,

-14 + (-14^2) = -14 + 196

= 182

8 0

3 years ago

A STATE PRIZE PAYS $1000 weekly for 15 years.

Doss [256]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Noah wants to create a floor plan that is a scale drawing. The actual length of Wall C is 4 m. To represent Wall C, Noah draws a

FinnZ [79.3K]

Answer:

Scale using for plan ⇒ 1 m = 4 cm

Step-by-step explanation:

Given:

Actual length of wall = 4 m

Segment of wall = 16 cm long

Find:

Scale using for plan

Computation:

Actual length of wall = Segment of wall

4 m = 16 cm

1 m = 16 / 4 cm

1 m = 4 cm

Scale using for plan ⇒ 1 m = 4 cm

7 0

3 years ago

Read 2 more answers

Which of the following functions have a vertical asymptote for values of Ø such that cos Ø = 1?Select all that apply.

igomit [66]

Answer:

$y=\cot \theta$ and $y=\csc \theta$

Step-by-step explanation:

Note that if $\cos \theta=1,$ then $\sin \theta=0.$

Functions $y=\cos \theta,\ \ y=\sin \theta$ do not have vertical asymptotes at all.

Vertical asymptotes have functions $y=\tan \theta,\ \ y=\cot \theta,\ \ y=\sec \theta,\ \ y=\csc \theta.$

Functions $y=\tan \theta$ and $y=\sec \theta$ have the same vertical asymptotes (when $\cos \theta =0$ ).

Functions $y=\cot \theta$ and $y=\csc \theta$ have the same vertical asymptotes (when $\sin \theta =0$ ). See attached diagram

3 0

3 years ago

An equation is shown. 2x-4y=8 solve the equation for x in terms of y

horrorfan [7]

2x-4y=8

Add 4y to each side to separate the variables, since you want to solve for x let be on the left

2x=4y+8

Divide the entire equation by 2 to allow x to stand alone

x=2y+4

And I have to type some more so it will let me answer the question so here ya go

7 0

3 years ago