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3 years ago

(factor out) 3x(to the power of 2) -39x+36

1 answer:

7 0

3x² - 39x + 36
3(x²) - 3(13x) + 3(12)
3(x² - 13x + 12)
3(x² - 12x - x + 12)
3(x(x) - x(12) - 1(x) + 1(12))
3(x(x - 12) - 1(x - 12))
3(x - 1)(x - 12)

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-15=-4m+5<br><br>8n+7=31<br><br>-10=10(k-9)

Korolek [52]

$-15=-4m+5\ \ \ |both\ sides\ /+4m\\\\4m-15=5\ \ \ \ |both\ sides\ /+15\\\\4m=20\ \ \ \ |both\ sides\ /:4\\\\\underline{\underline{m=5}}$

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$8n+7=31\ \ \ \ |both\ sides\ /-7\\\\8n=24\ \ \ \ |both\ sides\ /:8\\\\\underline{\underline{n=3}}$

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$10(k-9)=-10\ \ \ \ |both\ sides\ /:10\\\\k-9=-1\ \ \ \ |both\ sides\ /+9\\\\\underline{\underline{k=8}}$

6 0

3 years ago

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3x+y=4 <br> 2x-y=6<br> What is the answer to this equation?

nalin [4]

Answer:Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form(2,-2)

Equation Form:x=2 y=-2

Step-by-step explanation:

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3 years ago

What number should be added to both sides of the equation to complete the square? x^2-40x=0

mylen [45]

Answer:

+40

Step-by-step explanation:

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3 years ago

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PLEASE HELP FOR EACH OF THE FIGURES, WRITE AN ABSOLUTE VALUE EQUATION

Likurg_2 [28]

The solution set 0 and 8 are the true values of the absolute value equation

The absolute value equation that has the a solution set of 0 and 6 is |x - 3| = 3

<h3>How to determine the absolute value equation?</h3>

From the figure, the solution sets of the absolute value equation are given as:

x = {0, 6}

Calculate the mean of the solution set

Mean = 0.5 * (0 + 6)

Mean = 3

Calculate the difference of the solution set divided by 2

Difference = (6 - 0)/2

Difference = 3

The absolute value equation is the represented as:

|x - Mean| = Difference

Substitute known values

|x - 3| = 3

Hence, the absolute value equation that has the a solution set of 0 and 6 is |x - 3| = 3

Read more about absolute value equation at:

brainly.com/question/2166748

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2 years ago

2a2b3 and -4a2b3 are like terms.<br> True<br> False

stiv31 [10]

Answer:

Step-by-step explanation:

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3 years ago